필터 지우기
필터 지우기

I am having trouble doing integration for the following code.

조회 수: 1 (최근 30일)
I am having the following warning.
Warning: Infinite or Not-a-Number value encountered.
> In integralCalc/iterateScalarValued (line 349)
In integralCalc/vadapt (line 132)
In integralCalc (line 83)
In integral (line 88)
In Q2 (line 17)
clc
clear all
Fs= 2.16*10^-5*pi; % Geometrical Factor
h= 6.626*10^-34; % Plancks Constant
c= 3*10^8; % Speed of light
K = 1.38*10^-23; % Boltzmanns Constant
Ts=5760; % Temparature of the sun
E=0:0.5:4;
bs=((2*Fs)/((h^3)*(c^2))).*(E.^2./(exp(E./((K*Ts)-1))));
fun= @(E)(E.*((2*Fs)/((h^3)*(c^2))).*(E.^2./(exp(E./((K*Ts)-1)))));
Ps = integral (fun,0,Inf) ;
figure(2)
plot(E,Ps)

채택된 답변

Star Strider
Star Strider 2022년 2월 1일
The warning is likely the result of the second term, that becomes Inf at higher values.
Fs= 2.16*10^-5*pi; % Geometrical Factor
h= 6.626*10^-34; % Plancks Constant
c= 3*10^8; % Speed of light
K = 1.38*10^-23; % Boltzmanns Constant
Ts=5760; % Temparature of the sun
fun= @(E)(E.*((2*Fs)/((h^3)*(c^2))).*(E.^2./(exp(E./((K*Ts)-1)))));
Result1 = fun(0)
Result1 = 0
Result2 = fun(realmax)
Result2 = Inf
Check = @(E) E.^2/exp(E./((K*Ts)-1))
Check = function_handle with value:
@(E)E.^2/exp(E./((K*Ts)-1))
Check(realmax)
ans = Inf
I am not certain that there is any solution for that, other than restricting the upper integration limit to something smaller.
.

추가 답변 (1개)

Walter Roberson
Walter Roberson 2022년 2월 1일
Q = @(v) sym(v);
Fs = Q(2.16)*Q(10^-5)*Q(pi) % Geometrical Factor
Fs = 
h = Q(6.626)*Q(10^-34) % Plancks Constant
h = 
c = Q(3)*Q(10^8) % Speed of light
c = 
300000000
K = Q(1.38)*Q(10^-23) % Boltzmanns Constant
K = 
Ts = Q(5760) % Temparature of the sun
Ts = 
5760
E = Q(0):Q(0.5):Q(4);
bs = ((2*Fs)/((h^3)*(c^2))).*(E.^2./(exp(E./((K*Ts)-1))));
fun = @(E)(E.*((2*Fs)/((h^3)*(c^2))).*(E.^2./(exp(E./((K*Ts)-1)))));
syms x b real
assume(b >= 0)
Ps = int(fun(x), x, 0, b)
Ps = 
limit(Ps, b, inf)
ans = 

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by