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Equations to Matlab code

조회 수: 2 (최근 30일)
Maria
Maria 2014년 11월 18일
답변: Warren Dennis 2020년 2월 17일
hi
I want to convert the two equations below into Matlab code , I wrote the function below for that and I don't know if that is correct or not , specially the integral form ? any help ?
function [VI,Vw]= Modelfun(TL,TR)
dt=0.01; %sampling time
r=0.052;
L=0.306;
M=9;
I=5;
VI=(TL+TR)/ M * r;
VI=VI*dt/2; %first integral
Vw=(L*(TL-TR)) / 2 * r * I;
Vw=Vw*dt/2; %first integral
Vw=Vw*dt/2; %second integral
end

채택된 답변

Torsten
Torsten 2014년 11월 20일
It is not possible simply to output (VI,Vw) given (TL,TR).
As input you need (VIold,Vwold,Vwdotold,dt,TL,TR).
The output VI,Vw and Vwdot is then calculated according to
VI=VIold+dt*(TL+TR)/(M*r)
Vw=Vwold+dt*Vwdotold
Vwdot=Vwdotold+dt*L*(TL-TR)/(2*r*I).
This would mean that your function "Modelfun" advances VI and Vw from their values at time t to time t+dt.
Best wishes
Torsten.

추가 답변 (2개)

Torsten
Torsten 2014년 11월 18일
If the right-hand sides of your equations does not depend on t, the solution to your differential equations is explicitely given by
VI=VI0+(TL+TR)/(M*r)*t
Vw=Vw0+Vw0dot*t+0.5*L*(TL-TR)/(2*r*I)*t^2
where
VI0=VI at time t=0
Vw0=Vw at time t=0
Vw0dot = d/dt(Vw) at time t=0.
Best wishes
Torsten.
  댓글 수: 5
Maria
Maria 2014년 11월 19일
thanks a lot Torsten
Actually , I am not so good with Matlab and from my little bit understanding I built this function and I don't know if that right but generally what I want to do is to write the equations above in code form inside "Embedded MATLAB Function " block with two inputs(TL,TR) and two outputs (VI,Vw) as in figure above.
thanks
Maria
Maria 2014년 11월 20일
???

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Warren Dennis
Warren Dennis 2020년 2월 17일
k=k0e

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