detecting elements change in an array

I have an array of zeros:

x=zeros(1,36);

and in my program i change some elements of it to 1 using for example

x(6)=1;

Now i will turn some of those 1s to 2s, but is there a way i can say:

while all 1s didnt turn to 2s

.........

So basically i wanna keep inputting something as long as all the 1s didnt become 2s and it breaks out once all 1s became 2s

Answer 1

[Walter Roberson]

while any(x==1)

[Tariq Hammoudeh]

Thank you,

Answer 2

[Image Analyst]

Try this:

x=zeros(1,36);
% Get 20 random indexes to turn to 1's.
indexes = sort(randperm(length(x), 20));
% Initialize by turning some of the zeros into ones.
x(indexes) = 1;
% Set up a failsafe
maxIterations = 10000; % Way more than you think it would ever need.
loopCounter = 1;
% Now loop over the 1's, turning some of them to 2's
% until all the 1's have been turned into 2.
while any(x == 1) && loopCounter < maxIterations
    fprintf('Iteration #%d.\n', loopCounter)
    % Get indexes that are 1.
    indexes = find(x == 1)
    % Pick a random one of those to turn to a 2
    % or whatever method you want to use....
    randomIndex = randi(length(indexes))
    x(indexes(randomIndex)) = 2
    loopCounter = loopCounter + 1;
end
x
fprintf('All done after %d iterations.\n', loopCounter)