Tabulate variable inside a for loop
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I want to tabulate x1 and x2 for eah iteration as shown in below. Which commaned will help me to get this. I am quite new in Matlab.
ind =1;
L=length (x);
for i=1:100:L
newx = x(ind:i-1);
newy = y(ind:i-1);
Lx=mean(x(ind:i-1));
Ly=mean(y(ind:i-1));
x1=newx-Lx;
y1=newy-Ly;
ind = i;
end;
채택된 답변
Here's one way to do what I believe you want to do:
x = rand(1,1000);
y = rand(1,1000);
ind =1;
L=length (x); % assuming L is a multiple of 100
x1 = [];
y1 = [];
for i=101:100:L+1
newx = x(ind:i-1);
newy = y(ind:i-1);
Lx=mean(x(ind:i-1));
Ly=mean(y(ind:i-1));
x1(end+1,:)=newx-Lx;
y1(end+1,:)=newy-Ly;
ind = i;
end;
disp(x1);
disp(y1);
댓글 수: 5
Grytan Sarkar
2021년 12월 31일
편집: Grytan Sarkar
2022년 1월 1일
Voss
2022년 1월 1일
I'm not sure what you mean by x2, but I'll keep assuming that means y1. To get x1 and y1 in a table as columns, with the elements in each in the same order as the corresponding elements are in x and y:
x1 = reshape(x1.',[],1);
y1 = reshape(y1.',[],1);
t = table(x1,y1);
To put x1 and y1 as columns in a matrix instead of a table:
x1 = reshape(x1.',[],1);
y1 = reshape(y1.',[],1);
m = [x1 y1];
Grytan Sarkar
2022년 1월 1일
I made i start at 101 to avoid the first iteration of the loop not doing anything (ind:i-1 is empty when i and ind are both 1).
The reason you end up with less data is not because of the 101, but because L is not a multiple of 100. Notice the comment I put in the answer:
% assuming L is a multiple of 100
If L is not a multiple of 100, you're going to lose some data when you group it into blocks of 100 like this. But the code can be modified to handle a partial block on the end. One way to do so is to pad x and y with NaNs so that you have a multiple of 100 data points and then remove the extra NaNs at the end after making x1 and y1 into column vectors:
x = rand(1,2890);
y = rand(1,2890);
ind =1;
L=length (x);
rem_L = rem(L,100);
if rem_L > 0
x = [x NaN(1,100-rem_L)];
y = [y NaN(1,100-rem_L)];
use_L = L+100-rem_L;
else
use_L = L;
end
x1 = [];
y1 = [];
for i=101:100:use_L+1
newx = x(ind:i-1);
newy = y(ind:i-1);
Lx=mean(x(ind:i-1),'omitnan');
Ly=mean(y(ind:i-1),'omitnan');
x1(end+1,:)=newx-Lx;
y1(end+1,:)=newy-Ly;
ind = i;
end;
% reshape to columns
x1 = reshape(x1.',[],1);
y1 = reshape(y1.',[],1);
disp([x1(end-19:end) y1(end-19:end)]);
% cut off the extra NaNs:
x1 = x1(1:L);
y1 = y1(1:L);
disp([x1(end-19:end) y1(end-19:end)]);
Grytan Sarkar
2022년 1월 2일
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