Unable to compare equality of two matrices
조회 수: 1 (최근 30일)
이전 댓글 표시
I am trying to compare the two 4x4 matrices below and generate a success message, but I see that the code is able to display a success message only for the first element of each row. Can anyone spot where I made the mistake please?
Rotation_matrix = rotm2tform([0.9254 0.0180 0.3785; 0.1632 0.8826 -0.4410; -0.3420 0.4698 0.8138])
res = rpy2tr(30*pi/180,20*pi/180,10*pi/180)
k=0
for i = 1:size(Rotation_matrix)
for j = 1:size(res)
if isequal(i,j)
continue
else
disp("Fail")
k=1;
end
end
end
if k==0
disp("Verification success")
end
Thank you
댓글 수: 0
답변 (1개)
Walter Roberson
2021년 12월 27일
size() of a variable, when no option is provided in the size() call, always returns a vector, even if the variable is a scalar. When you use 1:size() then you are using 1 colon a vector . MATLAB does define that: it takes the first element of the vector. So 1:size(Rotation_matrix) is going to be the same as 1:size(Rotation_matrix,1) which might not be what you want.
Question: why are you comparing the indices instead of comparing the matrix indexed at the indices?
You should also read http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Multidimensional Arrays에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!