Using cellfun to extract specific rows from a cell array?

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omidm
omidm 2021년 12월 22일
댓글: omidm 2022년 4월 1일
Hello,
I have a 1x6 cell array, 'Peaks':
Peaks = {199x4500} {192x4500} {167x4500} {171x1950} {157x1500} {191x1500}
I would like to create a new cell array, 'New_Peaks' using only 16 rows from each cell. The row numbers I want to choose are are in a 16X6 double array, 'Indices'.
Indices =
2 1 1 1 4 1
16 23 7 72 133 24
44 30 19 15 13 63
41 15 28 9 18 58
35 26 31 3 15 4
8 49 39 19 53 32
11 72 40 96 29 64
14 39 55 73 111 84
153 33 57 129 12 71
70 116 63 92 75 60
144 104 95 94 68 83
137 137 97 108 77 74
91 155 107 140 120 97
36 40 119 49 144 56
80 64 127 105 43 59
160 94 145 66 149 49
I tried the following line:
New_peaks = cellfun(@(x) x(Indices), all_peaks, 'UniformOutput', false)
But the output is a 1x6 cell array consisting of 16x6 doubles.
The output I want is:
New_peaks = {16x4500} {16x4500} {16x4500} {16x1950} {16x1500} {16x1500}
Is cellfun able to extract the contents of a cell array in this way?
  댓글 수: 3
omidm
omidm 2021년 12월 22일
Hi, sure, uploaded the 'peaks' and 'indices' variables.
the cyclist
the cyclist 2021년 12월 23일
Separate piece of advice: Don't name a variable "peaks", which shadows the name of a function. That can cause issues and confusion.

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Matt J
Matt J 2021년 12월 22일
편집: Matt J 2021년 12월 23일
New_peaks =cellfun(@(a,b) a(b,:), Peaks,num2cell(Indices,1) ,'uni',0);
  댓글 수: 6
Matt J
Matt J 2022년 4월 1일
편집: Matt J 2022년 4월 1일
In that case, you can just use Indices in its current form.
New_peaks =cellfun(@(a,b) a(b,:), Peaks,Indices ,'uni',0);
I would also encourage you to read the cellfun documentation to understand what this is doing.
omidm
omidm 2022년 4월 1일
Great, thanks!

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