Error using horzcat in code trying to get rid of discontinuities

조회 수: 2 (최근 30일)
lena kappa
lena kappa 2021년 12월 22일
댓글: Voss 2021년 12월 22일
Hi everyone!
When i run this code
(it reads an image rotates it then gets 100 profiles of the same length from the image and then tries to eliminate the discontinuities in the profiles)
img101 = imread('c1=100.800.1.0.1.png');
img_rot= imrotate(img101,32.06);
for i=1:100
prof_img_rot(1:256,i)=img_rot(212+i,400:655)';
end
x_0 = [1 800];
y_0 = [1 501.06];
y = improfile(img101,x_0,y_0)
yOrig = y;
limit = 0.2;
dy = [0, diff(y)];
jump = strfind(abs(dy) > limit, [false, true, false]);
for ijump = 1:numel(jump)
k = jump(ijump);
y(k+1:end) = y(k+1:end) - dy(k+1);
end
figure
axes('NextPlot', 'add')
plot(x, yOrig, '-r', x, y, 'bo')
y2 = lowpass(y, 30, 200);
plot(x, y2, 'c+')
i get the next error:
Error using horzcat
Dimensions of arrays being concatenated are not consistent.
Error in lowpass_discontinuities_simple (line 34)
dy = [0, diff(y)];
Does anyone know why?
I have attached the image im reading

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Voss
Voss 2021년 12월 22일
This error happens because 0 is a scalar (i.e., it has size 1 in all dimensions) and diff(y) is of size not equal to 1 in some dimension(s) other than dimension 2, which is the dimension of concatenation with horizontal concatenation (i.e., using [] for concatenation), so that 0 and diff(y) cannot be horizontally concatenated. Try this instead:
dy = [zeros(size(y,1)-1,1,size(y,3)), diff(y)];
  댓글 수: 4
lena kappa
lena kappa 2021년 12월 22일
Thank you @Benjamin!!! It works great !!!

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