Mis match of dimensions

Suppose I want to find all maximum number in the matrix m:

I used this command line:

mm(:,:,j) = find( m(:,:,j) == maxlistm(:,:,j) );

If matrix m updated in each iteration, then next result for mm will be wrong. new mm dimension automatically will be match with the first mm (just repeat new maximum fined value).

Example: iteration 1:

m = [20;3;20;8;9;11;13;14;15;20];

then:

mm = [1;3;10]

now in iteration 2, m is:

m = [2;3;2;80;9;11;13;14;15;2];
then instead of given mm = [4], it will give me:

mm = [4;4;4] % 3 rows because in the first m, it found 3 max values

Answer 1

[Star Strider]

That result is most likely because you defined ‘mm’ as a 3-D matrix.

I would define it as a cell array instead. That will allow for varying numbers of returned values from your find call.

[Moe]

Thanks & you mean like this:

mm = find( m(:,:,j) == maxlistm(:,:,j) );

In this case, only last finding will be used in the calculation!

[Star Strider]

I was intending something like this:

mm{j} = find( m(:,:,j) == maxlistm(:,:,j) );

Note the curly brackets {} in the left side subscript reference mm{j}.

[Star Strider]

I’m not even getting that far.

It takes forever and I then get this error message:

Error using ones
Size inputs must be scalar.

Error in finalnov (line 1910)
    X2(:,:,j) = [a1(:,1), g2(:,:,j).*ones(size(a1),1)];

I’ll delete everything for the time being. When you get that sorted, attach your updated code.

[Star Strider]

Getting the same error with that version:

Error using ones
Size inputs must be scalar.

Error in star (line 141415)
    X2(:,:,j) = [a1(:,1), g2(:,:,j).*ones(size(a1),1)];

[Star Strider]

I don’t have any problems opening and reading it in xlsread or opening it in Excel.

The problem is with the size argument to ones. It is always a (1xN) vector (a scalar is (1x1)), where N is the number of dimensions of the argument. These lines will throw the same error:

q = rand(5,1);
r = ones(size(q),1);

I have no idea what you’re doing, so I can’t suggest a fix for it. If you want it to be size of ‘a1’, the correct syntax is:

ones(size(a1))