Figure out the waveguide width at cutoff (d) for each of TE0,TE1,TE2 and TE3 modes. Assume n1=1.48, n2=1.46 and wavelength is .82um. Sketch the transverse mode patterns (Ey(x)) at cutoff for TE0 and TE1.

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m=(2d/lambda)*(sqrt(n1^2-n2^2))
I am looking for the relation as given in the attachment.
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Star Strider
Star Strider 2014년 10월 30일
Download and attach the PDF to your original Question. (Use the ‘Edit’ function.) That way we know exactly what the problem statement is.
garry
garry 2014년 10월 31일
Okay... These are my two equations and i need to plot these in one graph...:-
Equation 1:- (22.2*10^3)*sin((161*10^4)*x) x < d/2
Equation2 :- (42.32*10^9)*exp(-2.896*10^6) x > d/2
here d/2 = 5*10^-6 m.

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Star Strider
Star Strider 2014년 11월 1일
Here you go:
d2 = 5E-6;
fv = @(x) [(22.2E+3)*sin((161E+4).*x).*(x<d2) + (42.32E+9)*exp(-2.896E+6.*x).*(x>=d2)];
x = linspace(0,2*d2);
figure(2)
plot(x, fv(x))
grid
producing:
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Star Strider
Star Strider 2014년 11월 10일
Communications engineering is far from my areas of expertise. I’m not at all familiar with the ‘FCS algorithm’. It might be best if you posted this as a new Question for others to see.

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