Thank you very much in advance.
a = [3 4 5 3 64 7 6 34 8 5 4 3];

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Stephen23
Stephen23 2021년 12월 6일
편집: Stephen23 2021년 12월 6일
Original question by Diego Rosendo Pérez retrieved from Google Cache:
I am given an array with different numbers and I have to compute the same array but with some values changed.
Hi, as you can see I am gven an initial array "a" and I have to create the code to return the same array but with some values changed according to some requirements I have to meet. Now, I have the values and their index but just do not know how to finish the exercise; I think that I need to use a for loop but I just do not know how to code the last line so that I obtain the same array "a" but with some values changed. Thank you very much in advance.
a = [3 4 5 3 64 7 6 34 8 5 4 3];
m = mean(a);
st = std(a);
an = abs(a - m) > st;
ind = find(an);

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답변 (1개)

Yongjian Feng
Yongjian Feng 2021년 11월 30일

0 개 추천

Do you mean:
a = [3 4 5 3 64 7 6 34 8 5 4 3];
m = mean(a);
st = std(a);
an = abs(a - m) > st;
ind = find(an);
a(ind) = an(ind)

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Yongjian Feng
Yongjian Feng 2021년 11월 30일
편집: Yongjian Feng 2021년 11월 30일
This one?
a = [3 4 5 3 64 7 6 34 8 5 4 3];
m = mean(a);
st = std(a);
an = abs(a - m) > st;
ind = find(an);
a(ind) = 4 % replace all the meet the requirements with 4

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도움말 센터File Exchange에서 Color and Styling에 대해 자세히 알아보기

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질문:

2021년 11월 30일

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2021년 12월 6일

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