How do I input a matrix (variable) in a function?
조회 수: 2 (최근 30일)
이전 댓글 표시
I created a function:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/145823/image.jpeg)
.
x is the excitation wavelength where i will input eg. " test,wavelength(765,y)"
.
y is a 729 by 1 matrix: .
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/145824/image.jpeg)
.
the result is:
.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/145825/image.jpeg)
.
where only the first number of y matrix is being implemented in the function. How do i create a function where the first number of y matrix will be implemented and return as a result as the first number in wavelengtha matrix and so on.
댓글 수: 1
the cyclist
2014년 10월 22일
The screenshots are very helpful in understanding your problem. I suggest not using them for the actual code, though, so that we can copy & paste your code into MATLAB ourselves.
채택된 답변
Mohammad Abouali
2014년 10월 22일
1) why you have comma in your function name?
2) Change your equation in element wise division as follow:
wavelengtha= 1./ ((1./x)-(y/10^7))
댓글 수: 3
Mohammad Abouali
2014년 10월 22일
One way is to do this:
let's say x=[765, 766, 777]
then you can do this:
for i=1:numel(x) wavelengtha{i}= yourFunction(x(i), ...) end
I still don't get the comma in your function name?
추가 답변 (1개)
the cyclist
2014년 10월 22일
I'm not sure I fully understand what you mean, but does this do what you intend?
wavelengtha = 1./((1./x) - (y/10^7));
Notice that I used element-wise division.
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrix Indexing에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!