mean of matrix elements

조회 수: 9 (최근 30일)
john creighton
john creighton 2014년 10월 15일
댓글: john creighton 2014년 10월 16일
hey all. i have a 5760x1 matrix. i need to find the average of the first 10 elements, remove the 10 elements and replave with the averaged number, find the average of the next 10 elements, remove those 10 elements and replace with average and so on.... could anyone give me an insight as to how to do this? much appreciated john

채택된 답변

Sean de Wolski
Sean de Wolski 2014년 10월 15일
B = mean(reshape(x,10,[]))'
Where x is your original column vector and B is the mean of every 10x1 chunk

추가 답변 (3개)

Andrew Reibold
Andrew Reibold 2014년 10월 15일
편집: Andrew Reibold 2014년 10월 15일
myMatrix = rand(5760,1)
for jj = 1:576
moving_avg(jj,1) = mean(myMatrix(jj*10-9:jj*10));
end
Will make a matrix called 'moving_avg' where each point represents the average of each set of 10 points.
Is that what you wanted? It will be 1/10 the size.
  댓글 수: 1
Andrew Reibold
Andrew Reibold 2014년 10월 15일
Its very easy to replace every single point with the average too if thats what you need. (Same size, but every set of 10 numbers are all the same averaged number.)

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Andrei Bobrov
Andrei Bobrov 2014년 10월 16일
I want have 'vote' too!
out = accumarray(ceil((1:numel(x))'/10),x(:),[],@mean);
  댓글 수: 2
Sean de Wolski
Sean de Wolski 2014년 10월 16일
b=blkproc(rand(5760,1),[10,1],@mean)
I can't think of a solution shorter than my reshape one in terms of Code Golf?
john creighton
john creighton 2014년 10월 16일
haha. yours works too...so well deserved 'vote' :)

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john creighton
john creighton 2014년 10월 16일
Both answers worked perfectly. Thanks guys. sorry can only accept one answer lol
  댓글 수: 1
Sean de Wolski
Sean de Wolski 2014년 10월 16일
You can vote too :)

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