replace values in char array if conditions are met

조회 수: 11 (최근 30일)
Nicholas Modar
Nicholas Modar 2021년 11월 3일
댓글: Dave B 2021년 11월 4일
I have a datestr of 15 minute data from a certain location (minDNB):
ex) minDNB = '00','15','30','45','00','15',30','45' etc.
my goal is to replace each value or create a new matrix with fractions of an hour:
goal: newminDNB = 0.00, 0.25, 0.50, 0.75, 1.00, 1.25, 1.50, 1.75, 2.00, etc.
How should I go about this? I would like to loop through minDNB because some time stamps are missing and I need to retain gaps in the data. Thanks.
time00 = '00';
time25 = '15';
time50 = '30';
time75 = '45';
A = size(minDNB)
for i = 1:numel(minDNB)
if minDNB(i) == time00
A(i) = 0.00;
else if minDNB == time25
A(i) = 0.25 ;
else if minDNB(i) == time50
A(i) = 0.50 ;
else if minDNB(i) == time75
A(i) = 0.75 ;
end
end
end
end
end

채택된 답변

Dave B
Dave B 2021년 11월 3일
편집: Dave B 2021년 11월 3일
I think your input is a cell array of character vectors:
minDNB={'00','15','30','45','00','15', '30','45'}
minDNB = 1×8 cell array
{'00'} {'15'} {'30'} {'45'} {'00'} {'15'} {'30'} {'45'}
and you want the output to be doubles, could you just do:
str2double(minDNB)/60
ans = 1×8
0 0.2500 0.5000 0.7500 0 0.2500 0.5000 0.7500
Or a fun alternative:
hours(minutes(str2double(minDNB)))
ans = 1×8
0 0.2500 0.5000 0.7500 0 0.2500 0.5000 0.7500
  댓글 수: 4
Nicholas Modar
Nicholas Modar 2021년 11월 3일
See attached. S is the structure with all station data. totalDNB is the full time stamp. minDNB and hourDNB are minute and hour seperated from the total date string.
The original data is in 15 minute intervals. My output needs to be in fractions of an hour. ( minute 15 -> minute 0.25)
My main point of confusion is how do I loop through the file the get 1) each fifteen minute interval converted to fractions of an hour and 2) how can I also keep the hour.
My desired output is a variable with size(minDNM). and somehow include the hours with minutes. (0.00 00.25 00.50 0.75 01.25 01.50 01.75 02.00...23.75 = 1 days worth of data. Let me know if I can explain further.
Dave B
Dave B 2021년 11월 3일
편집: Dave B 2021년 11월 3일
This is pretty similar to @Stephen's answer below but with a modification because your data are one big char and not a cell array of chars. I used double(string( for this but you could allso use str2double(cellstr(. And also I changed the < to a <= note this caveat:
if you're missing 1 or 2 consecutive measurements it's fine, if you want to increment the hour when you're missing 3 measurements (i.e. '00' '15' '30' '30' '45') then < should be <=, and if you're missing 4 measurements it's of course indistinguishable from just being the next hour!
mins=double(string(minDNB));
hrs = mins/60;
hrs=cumsum([0;diff(hrs)<0])+hrs;
But note: if you started with timeDNB, there's a way more natural path:
dt=datetime(timeDNB); % convert to datetime
hrs2=hours(dt-dt(1)); % or alternatively: [0;cumsum(hours(diff(dt)))]
This catches that you're missing measurements on March 11th (I think?)

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추가 답변 (1개)

Stephen23
Stephen23 2021년 11월 3일
C = {'00','15','30','45','00','15','30','45'};
V = str2double(C)/60;
V = V+cumsum([0,diff(V)<0])
V = 1×8
0 0.2500 0.5000 0.7500 1.0000 1.2500 1.5000 1.7500
  댓글 수: 3
Nicholas Modar
Nicholas Modar 2021년 11월 4일
Thanks everyone! Ended kind of combining everyones suggestions.
minDNB_fmt = datetime(dateDNB,'Format','mm');
hourDNB_fmt = datetime(dateDNB,'Format','HH');
minDNB = str2double(cellstr(minDNB_fmt));
hourDNB = str2double(cellstr(hourDNB_fmt));
duration_DNB = duration(hourDNB,minDNB,zeros(numel(minDNB),1));
[hh,mm] = hms(duration_DNB);
minutes_DNB = mm /60;
hourmin_DNB = horzcat(hh+minutes_DNB);
Dave B
Dave B 2021년 11월 4일
if you're just going through cellstrs to get from datetime to double, you can skip that step:
d=datetime(2010,1,1,10,30,00);
d.Hour
ans = 10
d.Minute
ans = 30

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