How to exclude min and max only once in a if statement?

Can anyone please tell me how when using an if statement and taking the mean of a vector of any size. when I take the mean of the vector I am asked if the vector has more than 6 elements exclude the min and max. But if the min or max occurs more than once only exclude it once.

so far I have ...

function ave = improvedMean(V1)
n = length(V1)
if n>0 %%n<= 5
 sum(V1) / n
elseif n >= 6
     ((sum(v1)-((min(v1)+(max(v1))) / (n-2)

I'm not sure where to go from there..

Answer 1

[Mohammad Abouali]

What you did was correct. Just add an "end" at the end of your code and change

if n>0 %%n<= 5

to

if n>0 && n<= 5

[Jason]

Thanks!!

Answer 2

[the cyclist]

function ave = improvedMean(V1)
n = length(V1)
if n <= 5
    ave = sum(V1) / n
else
    ave = (sum(V1)-(min(V1)+max(V1))) / (n-2)
end

[Jason]

thanks !!!

Answer 3

[José-Luis]

Can be done with logical indexing:

Edited to take into account the six elements limit

a = randi(10,[5,1]);
n = size(a,1);
s = sort(a);
cond = diff(s);
idx = ones(n,1);
idx([1 end]) = ~cond([1 end]) .*  n < 6;
your_mean = mean(s(logical(idx)));

[Mohammad Abouali]

But if the array is too large the sorting would be time consuming.

I think his approach is still better.

[José-Luis]

I am not sure I follow. You still need to find out whether the min and max values are repeated, which none of the posted answers does.

[Jason]

thanks!!

[José-Luis]

Please accept the answer that best solves your problem.