Split an array according to a logic
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Is there a way to split a vector ,
say;
[1 2 3 6 7 8 12 13 14 15 ] ....( the actual vector is much longer )
into preassigned groups or cells such that cosecutive numbers
{1 2 3 } { 6 7 8} {12 13 14 15} .... are grouped in different cells.
Thanks a ton.
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Jon
2021년 11월 1일
편집: Jon
2021년 11월 1일
If the numbers are ordered as you show them you can just use reshape() to make them into a m by 3 array. If you really need it to be a cell you can convert that using mat2cell
So for example
x = 1:30
X = reshape(x,10,3)
Xcell = mat2cell(X,ones(10,1))
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Jon
2021년 11월 1일
Oh, I see, I don't catch the last element in each group. I have to think about how to fix that.
Jon
2021년 11월 1일
편집: Jon
2021년 11월 1일
I think this now catches the end of each consecutive group too. Most of the logic is the same, but I realized you have to look forward and backward to see if they are consecutive and not miss the ends of the groups
% example vector containing groups of consectutive numbers
x = [1 2 3 6 7 8 12 13 14 15 18 19 20 31 35 36 40 41];
% elements are consecutive if they the next element is one larger than they
% are
idlFwd = [diff(x)== 1 0];
% elements are also consecutive if the one before them is one less than they are
idlBwd = [0 flip(diff(flip(x))== -1)]
% elements are consecutive if either criteria is met
idl = idlFwd|idlBwd;
% mark where beginning of each group of consecutive elements occurs, these
% are jumps from 0 to 1
iStart = diff([0 idlFwd])==1;
% count up jumps to form group numbers
groupCount = cumsum(iStart);
% assign group number, but only to ones that belong to a group (the
% consecutive values)
% (for non-members groupCount.*idl is zero so these are assigned to group
% zero)
group = groupCount.*idl ;
% loop through to assign to cell array by group
numGroups = max(group);
X = cell(numGroups,1);
for k = 1:numGroups
X{k} = x(k==group);
end
disp(X)
1 2 3 6 7 8 12 13 14 15 18 19 20 31 35 36 40 41
{[ 1 2 3]}
{[ 6 7 8]}
{[12 13 14 15]}
{[ 18 19 20]}
{[ 35 36]}
{[ 40 41]}
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