what does the "oldx =[x(n);oldx(1:256)]" in the following programm do?
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fid = fopen('bbg1AR20.sig', 'r');
x = fread(fid,'int16')
oldx = zeros(256,1);
for n = 1: 256000
oldx =[x(n);oldx(1:255)];
end
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David Hill
2021년 10월 28일
for n = 1: 256000
oldx =[x(n);oldx(1:255)];%just reforming the oldx array with x(n) on top and then the next 255 elements of oldx and dropping the last element
end
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dpb
2021년 10월 28일
It will (very inefficiently) append the first 255 elements of the (NEW and this is key) oldx vector onto the value of the read-in vector x after the Nth element, replacing the entire oldx vector on every pass through the loop. But, it is reversing x as it prepends it in front of the newly created vector each pass.
Whether this is the intent or not is probably debatable, but the above result is simply written as
oldx=[flipud(x);zeros(255,1)];
One might make presumptions of what was really intended, but that's what it does.
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