hi, i have a problem with ga function. the problem is: Caused by: Failure in initial user-supplied nonlinear constraint function evaluation.

조회 수: 3 (최근 30일)
my function is:
function f = obj_fun2(x)
MTTR = [0.04166666 0.041666667 0.083333333 0.041666667 0.041666667 0.083333333 0.041666667];
tic
S = zeros(1,320);
for j=1:320
S(j) = max([MTTR(1)*x(1,j), MTTR(2)*x(2,j), MTTR(3)*x(3,j), MTTR(4)*x(4,j), MTTR(5)*x(5,j), MTTR(6)*x(6,j), MTTR(7)*x(7,j)]);
end
toc
f = -((320 - sum(S))/320);
end
my constraint is:
function [c, ceq] = nlc(x)
for j=1:320
c(1) = -sum(x(1,:)) +(320/43.65);
c(2) = -sum(x(2,:)) +(320/43.71);
c(3) = -sum(x(3,:)) +(320/47.78);
c(4) = -sum(x(4,:)) +(320/89.66);
c(5) = -sum(x(5,:)) +(320/68.70);
c(6) = -sum(x(6,:)) +(320/29.22);
c(7) = -sum(x(7,:)) +(320/73.88);
end
ceq = [];
end
my model is:
nvars= 1;
intcon= 1:nvars;
LB = zeros(1,nvars);
UB = ones(1,nvars);
options = optimoptions(@ga,'SelectionFcn',@selectiontournament, ...
'FitnessScalingFcn',@fitscalingprop);
[x , fval] = ga(@obj_fun2 , nvars ,[],[],[],[], LB, UB , @nlc, intcon ) ;

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Alan Weiss
Alan Weiss 2021년 10월 19일
I believe that the error is here:
function [c, ceq] = nlc(x)
for j=1:320
c(1) = -sum(x(1,:)) +(320/43.65);
c(2) = -sum(x(2,:)) +(320/43.71);
% ...
end
end
You specify nvars= 1. However, your constraint function is trying to access x(2). Your x is a scalar. Error.
Alan Weiss
MATLAB mathematical toolbox documentation

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