# Use results in the definition of my functions

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Florian Spicher 2021년 10월 17일
댓글: Star Strider 2021년 10월 17일
I would like to use my X(i)s to define my function p, but it says that they are undefined variables or functions. How can I do?
A=[46/15, 5/2, 2/3; 5/2, 8/3, 1; 2/3, 1, 2];
B=[2*exp(1); 2*exp(1); 2*exp(1)-2];
X=linsolve(A,B)
integral(@(x) f(x),0,1)
function p=p(x)
p=X(1)*x.^2+X(2)*x+X(3);
end
function f=f(x)
f=(exp(x)-p(x)).^2;
end

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### 채택된 답변

Star Strider 2021년 10월 17일
function pv=p(X,x)
pv=X(1)*x.^2+X(2)*x+X(3);
end
Here, ‘X’ are the parameters and ‘x’ is the variable. Also, naming the variable inside the function to be the same as the function name confuses MATLAB (and everyone who reads the code).
Beyond that, what the problem and the desired result may be are both not possible to determine, and the parameters ‘X’ are nowhere either defined or calculated, so I’ll stop here.
.
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Star Strider 2021년 10월 17일
As always, my pleasure!
Since I don’t know the actual purpose of the code, I’m in no position to criticise its application. I’m just happy that I was able to help you get it to run! (I didn’t look carefully at the code the first time, so I didn’t notice that the ‘X’ parameters actually existed, and were calculated from the regression.)
.

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