How to plot a function with 3 independent variables

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Seng Hkawn N-Sang
Seng Hkawn N-Sang 2021년 10월 13일
댓글: Seng Hkawn N-Sang 2021년 10월 15일
f(x,y,z)=0.95*x+0.73*y+0.62*z-130.05
f(x,y,z); x; y; and z are values between 0 and 100.
f(x,y,z) is shown in color. How can I plot in MATLAB similar to figure below.
Thank you!

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KSSV
KSSV 2021년 10월 13일
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(0,100) ;
y = linspace(0,100) ;
z = linspace(0,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
isosurface(X,Y,Z,V,1e-4)
  댓글 수: 6
Walter Roberson
Walter Roberson 2021년 10월 14일
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(60,100) ;
y = linspace(60,100) ;
z = linspace(60,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
Vmin = min(V(:))
Vmin = 7.9500
Vmax = max(V(:))
Vmax = 99.9500
levels = 70:5:100;
Nlevels = length(levels);
cmap = hot(Nlevels);
for K = 1 : Nlevels
s = isosurface(X, Y, Z, V, levels(K));
p(K) = patch(s);
p(K).EdgeColor = 'none';
p(K).FaceColor = cmap(K,:);
isonormals(X, Y, Z, V, p(K));
end
camlight;
lighting gouraud;
xlim auto; ylim auto; zlim auto
view(3); view(36, 64);
legend(p, string(levels))
You cannot do contour lines because you are dealing with a 3D object: you can only do ISO surfaces.
It might be possible to get the colors right without some of the above steps. With the default steps I showed in https://www.mathworks.com/matlabcentral/answers/1562461-how-to-plot-a-function-with-3-independent-variables#comment_1783116 you might notice that the colors come out wrong compared to the legend: it turns out that you are looking at the "back" of the plates, and that you need to view() to see the front (or you need to move the light.)
Seng Hkawn N-Sang
Seng Hkawn N-Sang 2021년 10월 15일
Thank you both!
Got it working!

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