필터 지우기
필터 지우기

How do I define an output vector as real and positive

조회 수: 1 (최근 30일)
Christos
Christos 2014년 9월 21일
편집: Roger Wohlwend 2014년 9월 22일
Hi all
I am currently running this script to fit a complex function on my data using lsqcurvefit.
clear all;
hold off E1=importdata('E1.mat'); %E1 and DR1 are the names of my arrays
DR=importdata('DR1.mat');
hold on plot(E1,DR)
%x(1)=C
%x(2)=f
%x(3)=Eg
%x(4)=G
x0= [1 0 1 0.02 ];
F=@(x,E1)x(1)*exp(1i*x(2))./((E1-x(3)-1i*x(4))^2);
[x,resnorm,~,exitflag,output] = lsqcurvefit(F,x0,E1,DR);
plot(E1,F(x,E1),'--r')
hold off
It is working perfectly except for the part where all the fitted parameters are returned as complex numbers when they should be real and positive. Is there some way to fix this?
Thanks in advance
  댓글 수: 1
Star Strider
Star Strider 2014년 9월 21일
I don’t know what you are doing, but (from the Euler identities), exp(1i*x(2)) will be evaluated essentially as cos(x(2)) + i*sin(x(2)), and you are also multiplying x(4)^2 by 1i. If you do not want complex parameters, you will likely have to re-write your model. I would go to the literature to see what others have done in similar situations.

댓글을 달려면 로그인하십시오.

답변 (1개)

Roger Wohlwend
Roger Wohlwend 2014년 9월 22일
편집: Roger Wohlwend 2014년 9월 22일
The same question occured recently on Matlab answers: Link to the question.

카테고리

Help CenterFile Exchange에서 Get Started with Curve Fitting Toolbox에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by