break statement after if loop inside a for loop..

Hi..I have doubt if we are using an if loop inside a for loop followed by a break ,whether the break function will break if loop or for loop ..for example..

for i=1:100
if (statement1)
a=b
break 
end 
if (statement2)
b=c

in this which loop break will break ..if or for loop..

thanks

Answer 1

[Matt J]

The break will exit the for-loop. if...end's are not loops.

[Abhishek sadasivan]

I am trying to find how this(below) code is working ..can you able to me help me out.. q=0; k=1; locs_Rwave = [116 410 697]'; locs_Qwave=[110 210 356 457 575 313]'; for j=k:size(locs_Rwave) for i=1:numel(locs_Qwave) if (i== numel(locs_Qwave)) q=[q locs_Qwave(i)]; break; end if( locs_Qwave(i)>locs_Rwave(j)) q=[q locs_Qwave(i-1)]; break; end end end q

[Matt J]

Can't read it. You need to use the

formatting button. Also, now that you understand the behavior of break , what's left to explain?

[Abhishek sadasivan]

the code seems to very confusing ....pls have a look on the code ..

{ locs_Qwave=[ 100 150 90 1175 1 50]';

locs_Rwave=[116 170]';

q=0 k=1

for j=k:size(locs_Rwave)

    for i=1:numel(locs_Qwave)

        if (i== numel(locs_Qwave))
            q=[q locs_Qwave(i)];

            break;
        end

        if( locs_Qwave(i)>locs_Rwave(j))
              q=[q locs_Qwave(i-1)];
              break;

        end

    end

end

q }

[Matt J]

Please use the

button to font the code.

[Image Analyst]

Don't use a { before the code or a q} after the code. Other than that it should work, and the only problem is that you haven't read this: http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup