# Can I get the mathematical expression of an interpolation?

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Jaime De La Mota Sanchis 2021년 10월 8일
댓글: Steven Lord 2021년 10월 9일
Hello everyone. I am working with interpolated data.
I want to obtain the mathematical expression of the interpollating polynomial. I have written
sfX1 = fit([positions(:,1), positions(:,2)],windX_in_the_node_vector,'poly34')
And the output returns the linear model poly which is what I am looking for, f(x,y)=a*x^3+b*y^3+...
However, I would be interested in using other kinds of interpolations. I have tried linear, lowess, linearinterp, cubicinterp and nearest and instead of poly34. Unfortunately, instead of a polynomial such as the one in poly34, the code returns
Linear interpolant:
sfX2(x,y) = piecewise linear surface computed from p
Coefficients:
p = coefficient structure
and so on. Is there a way for me to obtain the mathematical expressions as the ones in poly34?
Best regards.
Jaime.
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Jaime De La Mota Sanchis 2021년 10월 8일
Hello. I think that would be very useful to me, as I feared, it seems like even if it can be done, a lot of work should be put in it.

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### 채택된 답변

Steven Lord 2021년 10월 8일
편집: Steven Lord 2021년 10월 8일
Are you looking for a mathematical expression for the fitted model or do you just want to be able to evaluate the fitted model at new points? In the former case, how were you hoping to use such an expression? If the latter case, that's easy.
f = fit(cdate, pop, 'linear', 'Normalize', 'on')
f =
Linear interpolant: f(x) = piecewise polynomial computed from p where x is normalized by mean 1890 and std 62.05 Coefficients: p = coefficient structure
plot(cdate, pop, 'r-+', 1977, f(1977), 'ko') % Evaluate f in 1977 Looks like a pretty good match.
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Steven Lord 2021년 10월 9일
The MATLAB Engine API for Python may be of interest to you.

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R2021b

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