How can I make a better plot?

조회 수: 3 (최근 30일)
HelpAStudent
HelpAStudent 2021년 10월 2일
댓글: HelpAStudent 2021년 10월 4일
Hi, I have 5 sets of data and I want to write a script that reads my 5 matrices (1x21 double) and displays a single figure that plots the mean error (y) against the gain (x) in decibel. The output of my script should has:
  • The lines for each segment should be displayed using a different color. With point where is the value on the segment.
  • A legend should be included indicating wich line corresponds to wich segment
  • Each segment should has his linear fit (courve fitting) in wich I can find the ratio between the axes
I think I have to use iteraction for a solution of this kind, but I'm not sure how.
These are my 5 data:
err20 = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1.08935539299999,2.06473429585112,5.31643514302866,12.1807063663099,23.4911626896201,37.8143988479465,53.0667200958471];
err40 = [1,1,1,1,1,1,1.00980392156863,1.21923952036955,1.83719863383950,3.35132045800776,6.15310998083444,10.4540779879203,16.3935058175317,24.4567825083250,34.2731876493287,44.8404803207833,56.1569894419756,67.9621753642978,80.3418716316936,92.6177152673935,105.509145868874];
err60 = [1.39130582788671,2.06089077044959,3.06870791245791,4.79824204787542,7.43102274858528,11.1839078762097,15.8879812010210,21.5982089544676,28.3128632729741,36.0451923666447,44.3639384800055,53.0905553702049,62.0750621155379,70.5611743877611,79.2822679481440,87.4151859346590,95.2561517964825,102.939651014533,111.592224212783,119.481125788707,128.101212449710];
err80 = [17.4311417284922,22.2395558126501,27.9265106941469,34.2412676054684,40.8661898327012,47.9425873245325,55.0569858602196,62.0452743182326,68.6517414695066,75.0178392624680,81.3553772590478,87.8836526599804,93.1726477983694,99.2482660012320,104.954811955097,110.618897123263,116.985855082487,123.136684599450,129.996356750259,137.015229368536,144.682941495957];
err100= [50.0098577942206,55.6474590816719,61.3114187709398,66.7658549295944,72.0226315556860,76.6917932491624,81.7675527655915,86.5206979973362,90.9380438970932,95.6093452209315,99.8809271502719,104.517882995723,109.232695936831,113.888646043589,118.823549750783,124.212683308618,129.481920951591,135.262067967506,141.525996933700,147.328685524455,153.893747639987];

채택된 답변

C B
C B 2021년 10월 2일
편집: C B 2021년 10월 3일
@Agnese Chini Is this fulfill your requirement?
err20 = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1.08935539299999,2.06473429585112,5.31643514302866,12.1807063663099,23.4911626896201,37.8143988479465,53.0667200958471];
err40 = [1,1,1,1,1,1,1.00980392156863,1.21923952036955,1.83719863383950,3.35132045800776,6.15310998083444,10.4540779879203,16.3935058175317,24.4567825083250,34.2731876493287,44.8404803207833,56.1569894419756,67.9621753642978,80.3418716316936,92.6177152673935,105.509145868874];
err60 = [1.39130582788671,2.06089077044959,3.06870791245791,4.79824204787542,7.43102274858528,11.1839078762097,15.8879812010210,21.5982089544676,28.3128632729741,36.0451923666447,44.3639384800055,53.0905553702049,62.0750621155379,70.5611743877611,79.2822679481440,87.4151859346590,95.2561517964825,102.939651014533,111.592224212783,119.481125788707,128.101212449710];
err80 = [17.4311417284922,22.2395558126501,27.9265106941469,34.2412676054684,40.8661898327012,47.9425873245325,55.0569858602196,62.0452743182326,68.6517414695066,75.0178392624680,81.3553772590478,87.8836526599804,93.1726477983694,99.2482660012320,104.954811955097,110.618897123263,116.985855082487,123.136684599450,129.996356750259,137.015229368536,144.682941495957];
err100= [50.0098577942206,55.6474590816719,61.3114187709398,66.7658549295944,72.0226315556860,76.6917932491624,81.7675527655915,86.5206979973362,90.9380438970932,95.6093452209315,99.8809271502719,104.517882995723,109.232695936831,113.888646043589,118.823549750783,124.212683308618,129.481920951591,135.262067967506,141.525996933700,147.328685524455,153.893747639987];
gain =1:21;
plot(gain,err20,'redo')
hold on
plot(gain,err40,'green*')
hold on
plot(gain,err60,'blue+')
hold on
plot(gain,err80,'cyanx')
hold on
plot(gain,err100,'magentad')
legend('err20','err40','err60','err80','err100')
ylabel('Error')
xlabel('Gain')
  댓글 수: 5
C B
C B 2021년 10월 4일
Maybe like this
p = polyfit(gain,err100,1) ;
slope5 = p(1)
HelpAStudent
HelpAStudent 2021년 10월 4일
Thank you, it works!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Legend에 대해 자세히 알아보기

제품


릴리스

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by