How to extract certain values from text file to find average of the group of numbers?

조회 수: 4 (최근 30일)
Can you please help me to extract certain column of numbers from a text file. I want to find their average. The following .txt file is as follows. I want only # 25 to 30 sigma values.
Number of unknowns: 1374
Number of observations: 28854 of 28854
Number of constraints: 1246
Number of datum stations: 14
Number of datum sources: 0
vTPv: 67100.6 +/- 1944.94
redundancy: 28726
chi^2: 1.5282 +/- 0.0220971
List of estimated parameters
.----------------------------------------------------------------------------------------------------.
| # | Type | member | reference epoch | sigma [unit] | repeatability [unit] |
|-------|-----------|----------|---------------------|-----------------------|-----------------------|
| 0 | PWL_CLK | AGGO | 2021.05.18 17:00:00 | 0.62888 [cm] | 1.99957 [cm] |
| 1 | PWL_CLK | AGGO | 2021.05.18 18:00:00 | 0.91947 [cm] | 4.93553 [cm] |
| 2 | PWL_CLK | AGGO | 2021.05.18 19:00:00 | 1.64927 [cm] | 8.35032 [cm] |
| 3 | PWL_CLK | AGGO | 2021.05.18 20:00:00 | 2.28501 [cm] | 10.70383 [cm] |
| 4 | PWL_CLK | AGGO | 2021.05.18 21:00:00 | 2.92039 [cm] | 12.11574 [cm] |
| 5 | PWL_CLK | AGGO | 2021.05.18 22:00:00 | 3.51718 [cm] | 12.86139 [cm] |
| 6 | PWL_CLK | AGGO | 2021.05.18 23:00:00 | 4.05227 [cm] | 12.85490 [cm] |
| 7 | PWL_CLK | AGGO | 2021.05.19 00:00:00 | 4.56631 [cm] | 12.34585 [cm] |
| 8 | PWL_CLK | AGGO | 2021.05.19 01:00:00 | 5.02033 [cm] | 11.29844 [cm] |
| 9 | PWL_CLK | AGGO | 2021.05.19 02:00:00 | 5.44759 [cm] | 10.22204 [cm] |
| 10 | PWL_CLK | AGGO | 2021.05.19 03:00:00 | 5.82947 [cm] | 9.16751 [cm] |
| 11 | PWL_CLK | AGGO | 2021.05.19 04:00:00 | 6.17638 [cm] | 8.30392 [cm] |
| 12 | PWL_CLK | AGGO | 2021.05.19 05:00:00 | 6.49624 [cm] | 7.89360 [cm] |
| 13 | PWL_CLK | AGGO | 2021.05.19 06:00:00 | 6.79364 [cm] | 7.92088 [cm] |
| 14 | PWL_CLK | AGGO | 2021.05.19 07:00:00 | 7.06446 [cm] | 8.59745 [cm] |
| 15 | PWL_CLK | AGGO | 2021.05.19 08:00:00 | 7.30998 [cm] | 9.59593 [cm] |
| 16 | PWL_CLK | AGGO | 2021.05.19 09:00:00 | 7.55144 [cm] | 10.44086 [cm] |
| 17 | PWL_CLK | AGGO | 2021.05.19 10:00:00 | 7.77601 [cm] | 11.36565 [cm] |
| 18 | PWL_CLK | AGGO | 2021.05.19 11:00:00 | 8.00764 [cm] | 11.76791 [cm] |
| 19 | PWL_CLK | AGGO | 2021.05.19 12:00:00 | 8.24088 [cm] | 11.82715 [cm] |
| 20 | PWL_CLK | AGGO | 2021.05.19 13:00:00 | 8.49287 [cm] | 11.09234 [cm] |
| 21 | PWL_CLK | AGGO | 2021.05.19 14:00:00 | 8.76043 [cm] | 9.66000 [cm] |
| 22 | PWL_CLK | AGGO | 2021.05.19 15:00:00 | 9.06284 [cm] | 7.28851 [cm] |
| 23 | PWL_CLK | AGGO | 2021.05.19 16:00:00 | 9.41047 [cm] | 4.15836 [cm] |
| 24 | PWL_CLK | AGGO | 2021.05.19 17:00:00 | 9.75290 [cm] | 1.99957 [cm] |
| 25 | PWL_CLK | HART15M | 2021.05.18 17:00:00 | 0.57717 [cm] | 1.75935 [cm] |
| 26 | PWL_CLK | HART15M | 2021.05.18 18:00:00 | 0.88342 [cm] | 4.97802 [cm] |
| 27 | PWL_CLK | HART15M | 2021.05.18 19:00:00 | 1.59244 [cm] | 8.59066 [cm] |
| 28 | PWL_CLK | HART15M | 2021.05.18 20:00:00 | 2.26089 [cm] | 10.78367 [cm] |
| 29 | PWL_CLK | HART15M | 2021.05.18 21:00:00 | 2.90160 [cm] | 12.28015 [cm] |
| 30 | PWL_CLK | HART15M | 2021.05.18 22:00:00 | 3.49047 [cm] | 13.06497 [cm] |
| 31 | PWL_CLK | HART15M | 2021.05.18 23:00:00 | 4.03382 [cm] | 13.11746 [cm] |
| 32 | PWL_CLK | HART15M | 2021.05.19 00:00:00 | 4.54147 [cm] | 12.73883 [cm] |
| 33 | PWL_CLK | HART15M | 2021.05.19 01:00:00 | 5.00205 [cm] | 11.97155 [cm] |
| 34 | PWL_CLK | HART15M | 2021.05.19 02:00:00 | 5.42749 [cm] | 10.89467 [cm] |
| 35 | PWL_CLK | HART15M | 2021.05.19 03:00:00 | 5.81582 [cm] | 9.73427 [cm] |

채택된 답변

Star Strider
Star Strider 2021년 9월 10일
Try this —
T1 = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/734899/Sujata%20Dhar%20%20text%20file%20-%202021%2009%2010.txt', 'VariableNamingRule','preserve');
sigma = regexp(T1{:,6}, '\d*.\d*[^[cm]]','match');
T2 = table(T1{:,2}, str2double([sigma{:}]).', 'VariableNames',{'#','sigma'})
T2 = 36×2 table
# sigma __ _______ 0 0.62888 1 0.91947 2 1.6493 3 2.285 4 2.9204 5 3.5172 6 4.0523 7 4.5663 8 5.0203 9 5.4476 10 5.8295 11 6.1764 12 6.4962 13 6.7936 14 7.0645 15 7.31
sigma_25to30 = T2.sigma(25:30)
sigma_25to30 = 6×1
9.7529 0.5772 0.8834 1.5924 2.2609 2.9016
or possibly —
sigma_25to30 = T2.sigma(T1.('#')>=25 & T2.('#')<=30)
sigma_25to30 = 6×1
0.5772 0.8834 1.5924 2.2609 2.9016 3.4905
I have no idea if this will work with the original text file because it never actually appeared as an uploaded/attached file. If there is a problem with it, use the one supplied here instead, since it works with my code.
Experiment to get different results.
.
  댓글 수: 4

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Whos에 대해 자세히 알아보기

제품


릴리스

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by