필터 지우기
필터 지우기

Stuck with simple matrix calculation, can you help?

조회 수: 2 (최근 30일)
Aaron Burdick
Aaron Burdick 2011년 8월 22일
So I have two matrixes, both 44x72, let's call them A and V. What I need to do is multiply each value in row/column "ij" by the same value in the other matrix. Then I need to sum all these values up and divide by the sum of all the values in matrix A. Here's another way to think about what I need to do:
Answer = Sum(Aij x Vij) / Sum(Aij) over all i,j grid cells
Sounds easy to do but I can't figure it out. Thanks in advance for the help!
Aaron

채택된 답변

Fangjun Jiang
Fangjun Jiang 2011년 8월 22일
B=A.*V;
SumA=sum(sum(A));
if SumA~=0
C=sum(sum(B))/SumA;
end
  댓글 수: 9
Sean de Wolski
Sean de Wolski 2011년 8월 23일
No, it can't easily be documented because it's system and version dependent: yours will surely be different than mine. This happened with Matt Fig and me on a question a few months ago. I had a vectorized solution that used big matrices, he used a well designed for-loop. Mine was much faster on my system, his was faster on his.
As for the (:), here are three methods for doing the sum. On mine the sum(sum()) is the fastest followed by reshape (with the numel(), reshape is slowed to the speed of a drunk turtle with a []) and then colon comes in third. I think the newer versions have a faster colon (<humor!>).
A = magic(1000);
[t1 t2 t3] = deal(0);
for ii = 1:100
tic
B = sum(sum(A));
t1 = t1+toc;
tic
C = sum(A(:));
t2 = t2+toc;
tic
D = sum(reshape(A,numel(A),1));
t3 = t3+toc;
end
[t1 t2 t3]
When I make A have more dimensions, say 5, both reshape and colon are faster. But for 2d stuff, sum(sum is fair.
Fangjun Jiang
Fangjun Jiang 2011년 8월 23일
Thanks Sean for the insight!

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Data Type Identification에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by