Simple Question ( for loop with differnt variables)

Heyho folks,
This is a really simple example for the Question I have.
for i=1:3
eval ( ['A' num2str(i) '=i'] )
end
generates A1 = 1 / A2 = 2 /A3 = 3
now i want to use these variables.....but how?
for i= 1:3
B = A{i} + 1
end %nope doesnt work
for i =1:3
B = ([A num2str(i)]) +1
end %nope doesnt work
............

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Azzi Abdelmalek
Azzi Abdelmalek 2014년 7월 15일
편집: Azzi Abdelmalek 2014년 7월 15일

0 개 추천

Why are you complicating things?
for i=1:3
A(i)=i
end
for i= 1:3
B(i) = A(i) + 1
end

댓글 수: 4

Well, the Problem is. This doesnt work.... I alraedy have the Variables A1 to A10 with Values. Now I want to use them as:
load('test.mat')
for i = 1:10
PlotData = A(i) % this is the important line
do some math.
end
So it takes A1 calculates....takes A2 calculates....
for k=1:3
eval(['data=' sprintf('A%d',k)])
%do
end
If you want to use A1, A2, etc. you will have to continue using eval. I recommend switching to an array or cell array, or even a structure, in order to better access your data.
Thanks, Guys...it worked....guess i am going to sleep now.....

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2014년 7월 15일

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