how to replace elements of a matrix in a sequence by comparing with another?

i have two matrix as

 y=[12 14 13 18 17 19 16 20 13 19 18];

 z=[1 2 3 4 5 6 8 9 10 12 14];

Now whenever there is a repetition in y, I want that value replaced by the values of z.

In the 9th position is '13' which is a repetition of 3rd position so that will get replaced by z's first value, which is '1', Then in 10th position is again a repetition so this '19' will get replaced by '2'. Same will happen whenever there is a repetition.

Please please help me out...

Answer 1

[Image Analyst]

It's not fancy, but did you try taking the histogram (to find integers with counts of 2 or greater) and then just the normal, brute force for loop to replace them with the numbers you want?

[suchismita]

actually i dont want any repetition in y if repeating than can i change with any number which is not there in y...like that way also can i do???? that also will work for me

[suchismita]

how can i replace the repetition values by anything else...?????

Answer 2

[Andrei Bobrov]

y = y(:);
z = z(:);
[~,b] = unique(y,'first');
c = setdiff(z,y);
ii = setdiff((1:numel(y))',b);
out = zeros(size(y));
jj = sort(b);
out(jj) = y(jj);
out(ii) = c(1:numel(ii));

[suchismita]

thank u so much....