rectangularPulse: no drop to 1/2 at edges
조회 수: 1 (최근 30일)
이전 댓글 표시
Hello I want to do the fourier of a rectangular pulse which is also 1 at the edges, so that the fourier returns a sinc function. rectangularPulse drops to 1/2 at the edges and does not seem to return the equivalent function if I plot the result vs. a sinc function. I tried ceil but this is not accepted with the fourier function.
Thanks a lot!
댓글 수: 0
답변 (2개)
Image Analyst
2014년 6월 27일
So just create it manually
myPulse = [0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ];
댓글 수: 2
Image Analyst
2014년 6월 27일
편집: Image Analyst
2014년 6월 27일
T's "Answer" moved here since it's not an answer to the original question.
I can't, the width of the rectangular pulse depends on a syms variable :/ And besides that, I dont think fourier(myPulse,f,y) would work then anymore anyway.
Image Analyst
2014년 6월 27일
Make it depend on the variable:
signalLength = 512; % whatever.
myPulse = zeros(1, signalLength);
startingIndex = 20; % Whatever
pulseWidth = 64; % Whatever, e.g. your syms variable value.
myPulse(startingIndex:(startingIndex + pulseWidth - 1)) = 1;
Matthew Suttinger
2018년 3월 30일
편집: Matthew Suttinger
2018년 3월 30일
If you don't mind converting it to a double after applying inputs, wrap the result in the ceil() function.
y = ceil(rectangularPulse(x_start,x_end,x_values));
class(y) % ans = 'double'
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Get Started with MATLAB에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!