how to create type of eye matrix

Hello, I have three matrix like:

z1=[5 0 1;7 9 0;10 0 0], z2=[0 1 2;5 8 0;3 9 10] and z3=[81 11 90;12 0 15;20 17 16]. you see that some of values in every matrix are zero. the number of cells that is not zero in z1 is 5 and in z2 is 7 and in z3 is 8. Now I want to make matrix on the basis of the structure of z1, z2 and z3 that has only zero and one like:

[1 1 1 0 1 0 1 0 0(on the basis of z1),0 0 0 0 0 0 0 0 0(on the basis of the number of z2),0 0 0 0 0 0 0 0 0(on the basis of the number of z3);0 0 0 0 0 0 0 0 0(on the basis of the number of z1),0 1 1 1 1 1 1 0 1(on the basis of z2),0 0 0 0 0 0 0 0 0(on the basis of the number of z3);0 0 0 0 0 0 0 0 0(on the basis of the number of z1),0 0 0 0 0 0 0 0 0(on the basis of the number of z2),1 1 1 1 0 1 1 1 1(on the basis of z3)]

Is there any idea and general way to create this matrix?

[dpb]

Please format the code/data matrices to be legible...

[1 1 1 0 1 0 1 0 0(on the basis of z1),0 0 0 0 0 0 0 0 0(on the basis of the number of z2),...

I can see that the first vector is

>> [z1(:)~=0].'
ans =
   1     1     1     0     1     0     1     0     0
>>

but I see no relationship between the rest and the given relationship. You're saying z2-->zeros(1,numel(z2)).

Need better explanation of the logic.

Answer 1

[Mischa Kim]

Fatema, use

 z_zero = blkdiag(z1(:)~=0,z2(:)~=0,z3(:)~=0)'

[fatema saba]

Thank you. you are kind angel.