Help with water-filling code (Revised Question)
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Hi
I wrote-in earlier but i was asked to review the question.
Question: 1. How do i make a “for loop” to occur in sequence without repeating the “for loop” over again? N:B in the iterative water-filling code i have repeated the “for loop” a number of times
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power3(i)=ini_power3(i)-increase;
end
if R(i)<R_T(i)
ini_power3(i)=ini_power3(i)+(increase);
end
end
2. If you run this code and then type R1, R2...R22 on the matlab command interface, you will get the corresponding values. From Question (1) above, how do i display the following? User 1: R1,R3,R5,R7,R9,R11,R13,R15,R17,R21 User 2: R2,R4,R6,R8,R10,R12,R14,R16,18,R22
3. How do i plot? User 1: y-axis: R1,R3,R5,R7,R9,R11,R13,R15,R17,R21 x-axis: 1:10 %number of iterations User 2: y-axis: R2,R4,R6,R8,R10,R12,R14,R16,18,R22 x-axis: 1:10 %number of iterations
%Iterative Water-Filling Algorithm
% =========================================================================
% Definition of Parameters
% ========================================================================
clear all
clc
% Defines the Target data rates to be occupied in two channels
R1_T = 0.512; % Mbps
R2_T = 0.512; % Mbps
R_T=[R1_T,R2_T];
% Initial Power Spectral Densities
ini_power1 = 0;
ini_power2 = 0;
ini_power3 = [ini_power1,ini_power2];
% Channel Matrix
h11 = 1e-6;
h12 = 1.1e-6;
h21 = 0.9e-6;
h22 = 1.3e-6;
gamma = 2;% snr_gap corresponding to Symbol error probability of 2e-4 and %coding gain of 4dB
% Cross-coupling = alpha1 & alpha2
alpha1 = gamma *(h11)^2/(h22)^2;
alpha2 = gamma *(h21)^2/(h11)^2;
% -80 dBm; the particular parts of noise-floor's %spectral density that %defines the spectral content of spectrum hole1 and hole2
noiseDensity = 1e-11;
% Noise terms = N1 & N2
N1 = gamma*noiseDensity/(h11)^2;
N2 = gamma*noiseDensity/(h22)^2;
% Resulting data = total capacity of a channel based on shanon theory
R1 = log2(1 + (ini_power1)/(N1+alpha2*ini_power2));
R2 = log2(1 + (ini_power2)/(N2+alpha1*ini_power1));
R=[R1,R2];
% Increase PSD by a factor of 3dB
increasedB=1.9952; % 3dB
increase=10^(increasedB/10);
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power3(i)=ini_power3(i)-increase;
end
if R(i)<R_T(i)
ini_power3(i)=ini_power3(i)+(increase);
end
end
R3 = log2(1 + (ini_power3(1))/(N1+alpha2*ini_power3(2)));
R4 = log2(1 + (ini_power3(2))/(N2+alpha1*ini_power3(1)));
R = [R3,R4];
ini_power4=[ini_power3(1),ini_power3(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power4(i)=ini_power4(i)-increase;
end
if R(i)<R_T(i)
ini_power4(i)=ini_power4(i)+(increase);
end
end
R5 = log2(1 + (ini_power4(1))/(N1+alpha2*ini_power4(2)));
R6 = log2(1 + (ini_power4(2))/(N2+alpha1*ini_power4(1)));
R = [R5,R6];
ini_power5=[ini_power4(1),ini_power4(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power5(i)=ini_power5(i)-increase;
end
if R(i)<R_T(i)
ini_power5(i)=ini_power5(i)+(increase);
end
end
R7 = log2(1 + (ini_power5(1))/(N1+alpha2*ini_power5(2)));
R8 = log2(1 + (ini_power5(2))/(N2+alpha1*ini_power5(1)));
R = [R7,R8];
ini_power6=[ini_power5(1),ini_power5(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power6(i)=ini_power6(i)-increase;
end
if R(i)<R_T(i)
ini_power6(i)=ini_power6(i)+(increase);
end
end
R9 = log2(1 + (ini_power6(1))/(N1+alpha2*ini_power6(2)));
R10 = log2(1 + (ini_power6(2))/(N2+alpha1*ini_power6(1)));
R = [R9,R10];
ini_power7=[ini_power6(1),ini_power6(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power7(i)=ini_power7(i)-increase;
end
if R(i)<R_T(i)
ini_power7(i)=ini_power7(i)+(increase);
end
end
R11 = log2(1 + (ini_power7(1))/(N1+alpha2*ini_power7(2)));
R12 = log2(1 + (ini_power7(2))/(N2+alpha1*ini_power7(1)));
R = [R11,R12];
ini_power8=[ini_power7(1),ini_power7(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power8(i)=ini_power8(i)-increase;
end
if R(i)<R_T(i)
ini_power8(i)=ini_power8(i)+(increase);
end
end
R13 = log2(1 + (ini_power8(1))/(N1+alpha2*ini_power8(2)));
R14 = log2(1 + (ini_power8(2))/(N2+alpha1*ini_power8(1)));
R = [R13,R14];
ini_power9=[ini_power8(1),ini_power8(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power9(i)=ini_power9(i)-increase;
end
if R(i)<R_T(i)
ini_power9(i)=ini_power9(i)+(increase);
end
end
R15 = log2(1 + (ini_power9(1))/(N1+alpha2*ini_power9(2)));
R16 = log2(1 + (ini_power9(2))/(N2+alpha1*ini_power9(1)));
R = [R15,R16];
ini_power10=[ini_power9(1),ini_power9(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power10(i)=ini_power10(i)-increase;
end
if R(i)<R_T(i)
ini_power10(i)=ini_power10(i)+(increase);
end
end
R17 = log2(1 + (ini_power10(1))/(N1+alpha2*ini_power10(2)));
R18 = log2(1 + (ini_power10(2))/(N2+alpha1*ini_power10(1)));
R = [R17,R18];
ini_power11=[ini_power10(1),ini_power10(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power11(i)=ini_power11(i)-increase;
end
if R(i)<R_T(i)
ini_power11(i)=ini_power11(i)+(increase);
end
end
R19 = log2(1 + (ini_power11(1))/(N1+alpha2*ini_power11(2)));
R20 = log2(1 + (ini_power11(2))/(N2+alpha1*ini_power11(1)));
R = [R19,R20];
ini_power12=[ini_power11(1),ini_power11(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power12(i)=ini_power12(i)-increase;
end
if R(i)<R_T(i)
ini_power12(i)=ini_power12(i)+(increase);
end
end
R21 = log2(1 + (ini_power12(1))/(N1+alpha2*ini_power12(2)));
R22 = log2(1 + (ini_power12(2))/(N2+alpha1*ini_power12(1)));
R = [R21,R22];
ini_power13=[ini_power12(1),ini_power12(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power13(i)=ini_power13(i)-increase;
end
if R(i)<R_T(i)
ini_power13(i)=ini_power13(i)+(increase);
end
end
R21 = log2(1 + (ini_power13(1))/(N1+alpha2*ini_power13(2)));
R22 = log2(1 + (ini_power13(2))/(N2+alpha1*ini_power13(1)));
R = [R21,R22];
ini_power14=[ini_power13(1),ini_power13(2)];
for i=1:2 %number of systems
if R(i)>(R_T(i)+(R_T(i))/100)
ini_power14(i)=ini_power14(i)-increase;
end
if R(i)<R_T(i)
ini_power14(i)=ini_power14(i)+(increase);
end
end
댓글 수: 2
Walter Roberson
2011년 8월 15일
Please take in to account time-zone differences. You posted your revised question after midnight everywhere in North America (other than Alaska); your repeated requests for assistance were at times when most people in North America were asleep, but people in Western Europe had not yet woken up.
답변 (1개)
Jorrit
2011년 8월 15일
1. You can probably make a double loop, a loop inside another loop. A second option is maybe to make a function out of it. I haven't looked at your code in depth, but it looks like there is a large amount of repetition.
2. & 3. Use logical indexing. Works for both displaying the numbers and plotting. You can use mod(n,2) for checking for even/odd numbers. to do this: n = 1:9;R(mod(n,2)==0) gives the 2nd, 4th, 6th etc entry. R(mod(n,2)==1) gives the 1st, 3rd, 5th etc entry.
댓글 수: 2
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