Read file
이전 댓글 표시
Hi all,
probably a very simple question..I need to read a text file consisting of a list of vectors with this format:
skip the first 22 line and then (x y z) (x y z) (x y z) ... (x y z)
there are 263853 line. How can i do that??
thanks for any help
andrea
답변 (3개)
Jan
2011년 2월 15일
The description of the file format is not exact enough. I'll show you a method for a well defined format and I assume you can adjust it to your needs:
I assume the file looks like this:
Header line 1
...
Header line 22
(0.1 0.2 0.3)
(0.17 19.5 231)
... <263853 of such lines>
This can be solved by TEXTSCAN or more low-levelish:
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
for iSkip = 1:22
dummy = fgetl(FID);
end
Data = fscanf(FID, '(%g %g %g)\n');
Data = transpose(reshape(Data, 3, []));
fclose(FID);
댓글 수: 2
Andrea Ferrari
2011년 2월 15일
Jan
2011년 2월 15일
Thanking is very polite. Accpeting an answer is helpful for others in addition.
Matt Tearle
2011년 2월 15일
Or, using textscan (as Jan mentioned):
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
Data = textscan(FID, '(%f %f %f)','headerlines',22);
x = Data{1};
y = Data{2};
z = Data{3};
fclose(FID);
카테고리
도움말 센터 및 File Exchange에서 Text Data Preparation에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!