array and minimum value and coordinate

Hi, everyone, first I want to explain my code.

that is, I am doing some iteration but iteration is done according to some criteria. I have 5 criteria and each criteria there some iterations. Program starts, criteria is selected then iterations is done. But after each iteration, error is calculated according referance value. So that I want to put all error in array and find their minimum. But I also have to know that minumin error belongs which criteria and which iteration.

can u help me about this ?

king regards

[Azzi Abdelmalek]

This not clear, maybe if you post your code, things will be clear

Answer 1

[dpb]

Basically, preallocate an array of the size of number of criterion (5) by the number of pieces of data you want to keep (in your description I see

• the iteration number/identifier
• the error for the particular criterion

So,

errarray=zeros(5,2);   % allocate room
index=0;               % an index variable for which we're on...
%do iteration one here...
index=index+1;
errarray(index,1)=iteration;         % save the iteration value
errarray(index,2)=result-refvalue;   % and the error
%do iteration two here...
index=index+1;
errarray(index,1)=iteration;              % save the iteration value
errarray(index,2)=abs(result-refvalue);   % and the error
% lather, rinse, repeat...

When done w/ all five, then

errarray=sortrows(errarray,2);      % sort by error column
error=errarray(1,:);                % the first row is the minimum and the aux value with it

You can also use

[emin,idx]=min(errarray(:,1));      % find the minimum and location thereof
error=errarray(idx,:);              % idx is the row of the minimum

If your repeat is a loop or a nest of multiple loops, just rearrange the linear path above within that structure.

[BARAN Özbakr]

thanks for answer, but the problem is that for example; criteria5 have 3 iteration but criteria1 has only 1. What can I do in this situation ?

[dpb]

Add enough dimensions to account for the number of variables need or use cell arrays to hold different numbers of items per cell.

Need a better outline of the actual code as Azzi notes to do more than generic answers as given.