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Doubts with parfor loop

조회 수: 2 (최근 30일)
Javier
Javier 2011년 7월 29일
Hi, I'm a litte bit confused with error given in this parfor loop:
parfor n=1:fbaseDatosAct
veDelanteMiaTemp=zeros(1,3);
baseDatosRow = baseDatosAct(n,:);
veDelanteMiaTemp=vehDelanteMia(baseDatosAct,n,t);
[baseDatosRow(1),estaParado]=reduceVelocidad(t,baseDatosRow,vmin,veDelanteMiaTemp,pasoTemp);
baseDatosAct(n,:) =baseDatosRow;<-HERE TROUBLE WITH PARFOR!!
end
Why in the last sentence do I get a error saying that I cannot use parfoor loop due to the baseDatosAct use?? I've got another code whit a similiar use and I don't get this warning.
Another doubt, I can use pafor loop with logical indexing a matrix like this:
for n=1:1:fbDActual
indice=find(bDAnterior(:,columnaID)==bDActual(n,columnaID));
do something...
end
end
Where bDAnterior and bDActual both are matrixes of nx8.
Thanks Javier

답변 (1개)

Edric Ellis
Edric Ellis 2011년 8월 1일
The problem is that you're using the whole value of 'baseDatosAct' in the line:
veDelanteMiaTemp=vehDelanteMia(baseDatosAct,n,t);
Is that what you intended? If so, the loop is not order-independent because you're updating 'baseDatosAct' and using the values next time around the loop.
  댓글 수: 1
Javier
Javier 2011년 8월 1일
Yes it was. I have to use the whole value of 'baseDatosAct' in the function,however, I found out a solution doing this:
bdAct=zeros(fbaseDatosAct,cbaseDatosAct);
bdAct=baseDatosAct;
parfor n=1:fbaseDatosAct
veDelanteMiaTemp=zeros(1,3);
baseDatosRow = bdAct(n,:);
[veDelanteMiaTemp(1),veDelanteMiaTemp(2),veDelanteMiaTemp(3)]=vehDelanteMia(baseDatosAct,n,t);
[baseDatosRow(1),estaParado]=reduceVelocidad(t,baseDatosRow,vmin,veDelanteMiaTemp,pasoTemp);
bdAct(n,:) =baseDatosRow;
end
baseDatosAct=bdAct

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