How to get Index of matrix after Max and Min

for example

a=[1 2 3; 4 5 6];

b=max(min(a);

what i want,

for min(a)=[1 4]' , index(1,1 2,1)

b=max(min(a))= 4 , index as 2,1

how can i do this? i require the final index as said above. what is the code for it.

Answer 1

[Mischa Kim]

Praveen, use something like

 ind = arrayfun(@(ii) find(a(ii,:)==min(a(ii,:),[],2)),1:size(a,1));

to get the column indices of the row minima, and

 [r c] = find(a == max(min(a,[],2)));

[Julian]

The first expression

[r c] = find(min(a,[],2));

is independent of the content of a. r & c will depend only on the size(a,1). r will be [1:size(a,1)]' while c will be ones(size(a,1),1) for any a!

max() and min() return the index of the located minimax in the 2nd argument.

[Mischa Kim]

Thanks for the catch.

[Praveen]

thank you for your response,

i used [k,v]=max(min(b));

where k gives the value and v gives the index. for my problem this was enough as

min(a)=[1 2 3] [k,v]=max(min(b)); output : k=3 v=3. this one solved my problem. thank you for your other choices , i will try them in future.