for loop with eval and sprintf with underscore in

조회 수: 27 (최근 30일)
Elisa
Elisa 2014년 4월 7일
편집: Stephen23 2023년 11월 14일
Sorry about that,
I've been trying really hard to find any solution from other answers, but or I don't understand them or it doesn't work.
I've also red that is bad to dynamically use 'eval' and 'sprintf', however, even though I'm willing to learn, I am not able to do in another way (and I've tried it).
I've many .txt file:
X12345678_1_ABC_ABCD_ABCDE_ABCDEF.txt
% Load .txt files into workspace
files = dir('*.txt');
for i=1:length(files);
eval(['load ' files(i).name ' -ascii']);
end
%% I dynamically try to do something with my variable
for i=1:length(files);
filename = files(i).name(1:end-4); %%%I get out the .txt
temp = eval(sprintf('X%s\_1\_ABC\_ABCD\_ABCDE\_ABCDEF',filename));
%insert the matrix of the text file into a new 3D matrix
threeD_matrix (i,:,f) = temp;
end
Warning: Escape sequence '_' is not valid. See 'help sprintf' for valid escape sequences. Error using eval Undefined function or variable
Thank you so much for your help!!!!!
  댓글 수: 1
Stephen23
Stephen23 2023년 11월 14일
편집: Stephen23 2023년 11월 14일
"I've many .txt file: X12345678_1_ABC_ABCD_ABCDE_ABCDEF.txt"
The simple solution is to avoid LOAD for textfiles. Use READMATRIX, READTABLE, etc.
At the time this question was posted, CSVREAD or DLMREAD would likely have worked.

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답변 (2개)

Jan
Jan 2014년 4월 7일
Two general advices:
1. Avoid eval in general:
eval(['load ' files(i).name ' -ascii']);
Better:
load(files(i).name, '-ascii');
2. Join folder names by fullfile instead of sprintf with hard coded separators.
  댓글 수: 1
Elisa
Elisa 2014년 4월 8일
Thanks Jan! I didn't know, who to do it! I'll follow your tips for next time! Thanks a lot!

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Star Strider
Star Strider 2014년 4월 7일
편집: Star Strider 2014년 4월 7일
To put a backslash (\) into a string, you need to use a double backslash (\\):
filename = 'myfile.txt';
R = sprintf('X%s\\_1\\_ABC\\_ABCD\\_ABCDE\\_ABCDEF', filename)
produces:
R =
Xmyfile.txt\_1\_ABC\_ABCD\_ABCDE\_ABCDEF
The ‘eval’ function is not considered efficient programming practice, but it may be the only way to get a variable generated as a string into the workspace as a variable. It is not really ‘wrong’ though.
  댓글 수: 10
Star Strider
Star Strider 2014년 4월 7일
이동: Voss 2023년 11월 14일
My pleasure!
Sorry for the delay — sleeping here (GMT-6).
Star Strider
Star Strider 2014년 4월 7일
My pleasure!
Sorry for the delay — sleeping here (GMT-6).

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