How to convert string to numeric variable in if statement
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I want to covert my string variable into numeric variables.
I have got string Variable Team that shows which players are in. For example C2, C1, B2, B1 etc.
I want to give each player a numeric value which represents the team.
I tried the following
for i =1:length(Team)
if Team(i) strcmp 'C1'
Team(i) = 1
elseif Team(i) strcmp 'C2'
Team(i) = 2
end
end
but get the error:
??? Conversion to logical from cell is not possible.
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채택된 답변
Jos (10584)
2014년 3월 5일
AllTeams = {'A1','B1','C1','C2','C3'} % all the teams
Team = {'A1','B1','C1','A1','C3','A1','unknown','C1'} % Team{k} is the team of player k is
% map team names to numbers
[~,TeamNumber] = ismember(Team, AllTeams)
X = find(TeamNumber <= 2) % players in team 1 or 2
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추가 답변 (2개)
Chandrasekhar
2014년 3월 5일
for i =1:length(Team)
if Team(i)== str2num(C1)
Team(i) = 1
elseif Team(i)==str2num(C2)
Team(i) = 2
end
end
댓글 수: 5
Chandrasekhar
2014년 3월 5일
Ok..can you explain the logic clearly
what does the array team contain? and what exactly you want to find?
Giorgos Papakonstantinou
2014년 3월 5일
편집: Giorgos Papakonstantinou
2014년 3월 5일
If this is exactly what you want to do then try this:
Team = {'C1' 'C2' 'C3' 'C4'}
for ii=1:length(Team)
switch Team{ii}
case 'C1'
Team{ii} = 1;
case 'C2'
Team{ii} = 2;
case 'C3'
Team{ii} = 3;
case 'C4'
Team{ii}=4
otherwise
fprintf('hallo')
end
end
But you change the variable Team... Maybe you assign the numbering to a new variable.
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Giorgos Papakonstantinou
2014년 3월 5일
cell2mat(Team)
But in this way you alter the variable Team. Why don't you try this:
[~,B] = ismember(Team, {'B1' 'B2' 'C1' 'C2'})
It will have the same effect. You will not alter the cell Team. Instead you create a new variable B which is the same with the one you asked for.
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