parallel processing time is bigger,
이전 댓글 표시
I have a code comparing a to process using parfor and for, but the time of the parfor is bigger thans using "for". here below the program:
Count=12000000;
MSB=A(2:2:Count);
LSB=A(1:2:Count);
DiffB=zeros(Count/2,1);
B=DiffB;
tic
for i=2:2:Count
B(i/2)=A(i)*256 + A(i-1);
end
for j=1:size(B,2)-1
if((B(j+1)==0) && (B(j)==4095))
DiffB(j)=1;
else
DiffB(j)=B(j+1)-B(j);
end
end
t1=toc
tic
parfor i = 1:Count/2
B(i)=MSB(i)*256 + LSB(i);
end
C=B;
parfor j=1:size(B,2)-1
if((B(j+1)==0) && (C(j)==4095))
DiffB(j)=1
else
DiffB(j)=B(j+1)-C(j);
end
end
t2=toc
matlabpool close
disp('Tiempo differencia')
t2-t1
time for "FOR" is 0.6016 sec and the time for "PARFOR" 5.5039 sec can someone can tell me what did I make wrong?
답변 (1개)
Matt J
2014년 2월 21일
0 개 추천
Are you running inside a script or in an mfile function? Try both.
댓글 수: 2
But aside from that, your compute-to-memory-access ratio looks very small. You are doing very little computation inside the loops for every element of data (LSB(i), MSB(i), etc...) that you are sending to the workers. PARFOR is intended for a situations where you are doing a lot more computational work inside the loops.
Julio
2014년 2월 23일
카테고리
도움말 센터 및 File Exchange에서 Parallel for-Loops (parfor)에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!