error with 20x10 array in a function
조회 수: 1 (최근 30일)
이전 댓글 표시
Hi;
Im having this error when i run "fcp" function (detailed below).
??? Attempted to access ASEB(1,1); index out of bounds because size(ASEB)=[0,0].
Error in ==> fcp at 15
Vsal(x)=ASEB(i,j);
Working out of the function, all variables load but it seems ASEB is not operating in the function.
Hope someone can help me
function [ Cp ] = fcp( beta,lambda )
%FCP Summary of this function goes here
% Detailed explanation goes here
global ASE
%ASE matrix loaded in workspace previously
ASEB=(0.0003*beta.^3 -0.0044*beta.^2 -0.0479*beta + 1.0850)*ASE;
x=0;
for i=1:20;
for j=1:10;
x=x+1;
Vsal(x)=ASEB(i,j);
end;
end;
%como el vector Vsal tambien se reduce en abcisas, habra que multiplicarlo
%de nuevo por otra funcion de B
fB2=(0.0026*beta.^2 -0.1031*beta + 1.2393);
Vsal=fB2*Vsal;
i=(200/20)*lambda;
fix(i);
Cp=Vsal(i);
end
댓글 수: 1
Wayne King
2014년 2월 13일
Please format your code and you need to tell us the size of beta and lambda, give us some representative values.
채택된 답변
Rizwana
2014년 2월 14일
Your ASE is matrix of what size?? Must be huge.. try to loop it...
r = size (ASE);
for i = 1:r(1) % 1:r(2) assuming it is column-vector.
values = Asme(:,1); %reads all values
ASEB=(0.0003*beta.^3 -0.0044*beta.^2 -0.0479*beta + 1.0850)* values;
output(i,:) = ASeb;
end
outputfilename = ['output\' outputfilename];
dlmwrite(outputfilename,output, '\t');
% now use this aseb for further calculations... I hope i got this question right. Since you are not looping over your values, it is storing only last set of data
댓글 수: 0
추가 답변 (1개)
Andrei Bobrov
2014년 2월 13일
편집: Andrei Bobrov
2014년 2월 14일
function Cp = fcp( beta,lambda )
global ASE
Vsal = polyval(conv([0.0003,-0.0044,-0.0479,1.085],...
[0.0026,-0.1031,1.2393]), beta)*reshape(ASE',[],1);
Cp = [];
try
Cp = Vsal(fix(10*lambda));
catch
disp('Look size of ASE and value of lamda');
end
end
댓글 수: 0
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!