its not taking the values of y when y value is ranging from 0.25 to 0.45 with an interval of 0.05,but it is able to take the value when y value is constant. and its coming in some matrix but with constant values.
이전 댓글 표시
Y1 = 7.7054
Y2 = 9.6584
I(3)= -0.0043
I(4)=0.4141
n=4 ;
m=2;
y=0.25:0.05:0.45;
for j=1:m
for i=1:n
if (j==1)
ud(i+1,1)=y;
taub(i+1,1)=y;
ud(i+1,2)=(I(3)*exp(Y2*y)+I(4)*exp(-Y2*y)+k2)^0.5;
taub(i+1,2)=(f*ro*ud(i+1,2)^2)/8;
end
end
end
ud
taub
plot(ud(i,1),ud(i,2))
sir here y will be my first column and ud will be my second column,bt ud is dependent on y,y is varying from 0.25 to 0.45 by having an interval of 0.05. here i just want to change the value of y in each iteration.
댓글 수: 7
ES
2014년 1월 23일
Shouldn't you be using y(i) instead of y alone in the lines
ud(i+1,1)=y;
taub(i+1,1)=y;
ud(i+1,2)=(I(3)*exp(Y2*y)+I(4)*exp(-Y2*y)+k2)^0.5;
Also what is k2?
ellora
2014년 1월 24일
Image Analyst
2014년 1월 24일
But we don't know if y should really be y(j) or y(i). y has 5 elements, not 2 or 4 like m and n.
ellora
2014년 1월 24일
Image Analyst
2014년 1월 24일
Is "the table" what you call "taub"? And by "find" you really mean "assign"? Or do you really mean "find" as in search for, or identify the location of?
ellora
2014년 1월 25일
ellora
2014년 1월 26일
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