I have a matrix containing force on 5 particles in three dimensions.

F =

   66.3101  180.9273  312.7912
   43.8362  180.3707  304.0829
    4.6838  296.7552   89.7479
   39.1522  298.8534  136.5975
    1.4743    5.9048   63.5243
first row represent force on 1st particle in three directions respectively.Now i want to solve the differential equation D2x =F(:,1)   D2y=F(:,2)  D2z=F(:,3) for each row so how should i do it?

[Youssef Khmou]

can you provide more inputs and the nature of the solution you seek?

[Sangeeta Ydaav]

initial velocity is zero

Answer 1

[Youssef Khmou]

if you have initial velocity and position values (vx,vy,vz,x,y,z) then you need add them after each integration, otherwise, you can use integral function to get X,Y,Z as follows :

X=integral(integral(F(:,1),0.1),0.1); 
Y=integral(integral(F(:,2),0.1),0.1);
Z=integral(integral(F(:,3),0.1),0.1);

[Sangeeta Ydaav]

I think this integration will give velocity .I need positions ao i think i should integrate again after adding initial velocities

[Youssef Khmou]

In this case yes :

 VX=integral(F(:,1),0.1)+VX0;
 X=integral(VX,0.1);