continue statment not executing correctly within for loop

I have the following code:

for i=1:length(files)
   for j=1:length(files(i,1).day)
               if ((1:length(files(i,1).day(j).hour)) ~=  24) 
                   continue
               end
              for h = 1:24
                   if ((1:length(files(i,1).day(j).hour(h).halfhour)) ~= 2)
                       continue
                   end 

                 if isempty(1:length(files(i,1).day(j).hour))
                     continue
                 end
                 dayPSD = [];
                 for h2=1:2 
                     dayPSD = [dayPSD; files(i,1).day(j).hour(h).halfhour(h2).data{8}'];  
                    end
                end
end
end

where

      files=1x3 structure
      files(i,1).day=1x335 structure that contains 1 field hour which is a 1x24 structure
      files(i,1).day.hour=1x24 structure that contains 1 field halfhour which is a 1x2 structure

I am trying to loop through i and j, but when 1:length(files(i,1).day(j).hour) ~= 24 (so when the hours are less than 24) I would like to exit the loop and continue onto the next iteration of the for loop. I would also like it to exit the loop and continue onto the next iteration of the for loop if 1:length(files(i,1).day(j).hour(h).halfhour) ~= 2 (so when the half hours are less than 2) or if 1:length(files(i,1).day(j).hour is an empty cell (no data).

The current code I have written only seems to skip a loop index if 1:length(files(i,1).day(j).hour ~=24.

What am I doing wrong? Also how do I get it to continue onto the next iteration if any of those conditions are met? I've been banging my head on this for a while, and I know I'm probably making a simple mistake, but if anyone can point me in the right direction that would be great.

Thanks for your help in advance!

Here's the updated answer after Jan's input and a little bit of tweaking:

for i=1:length(files)
 for j=1:length(files(i,1).day)
               if ((length(files(i,1).day(j).hour)) ~=  24)
                   continue
               end
               for h=1:24
               if ((length(files(i,1).day(j).hour(h).halfhour)) ~= 2) 
                   break
               end
               if isempty(1:length(files(i,1).day(j).hour))
                   break
               end
              dayPSD = [];
              numDayPSDs = 0;
                  for h2=1:2 
                          dayPSD = [dayPSD;    files(i,1).day(j).hour(h).halfhour(h2).data{8}'];
                          numDayPSDs = numDayPSDs+1;   
                  end
              end

Thanks!

Answer 1

[Jan]

What is the intention of this line:

if ((1:length(files(i,1).day(j).hour)) ~=  24)

Perhaps you mean:

if length(files(i,1).day(j).hour) ~=  24

If files(i,1).day(j).hour is a vector, 1:files(i,1).day(j).hour is the vector from 1 to the first element of files(i,1).day(j).hour .

You can use the debugger to investigate such problems. Set a breakpoint in this line and check the values in the command line:

(1:length(files(i,1).day(j).hour)) ~=  24
1:length(files(i,1).day(j).hour)
length(files(i,1).day(j).hour)
files(i,1).day(j).hour

It is a bug (beside the same "1:x" problem) to check

if isempty(1:length(files(i,1).day(j).hour))

after

if ((1:length(files(i,1).day(j).hour(h).halfhour)) ~= 2)

If hour is empty, you cannot access files(i,1).day(j).hour(h).halfhour .

[Katherine]

You are right Jan, I was actually never meeting at least my second condition because I was comparing a vector with a scalar resulting in a vector of a boolean. I ended up changing both conditions and adding in some breaks out of the h loop to fix this. Thanks!