you will provide both the code and snapshots of the generated output.

Assume that a signal x(t) has the following Fourier coefficients:

a_0=1
a_1=a_(-1)=1/4
a_2=a_(-2)=1/2  
a_3=a_(-3)=1/3

These coefficients correspond to seven harmonic components of the signal x(t). Plot the harmonic components corresponding to k=0, k=1 and k=-1, k=2 and k=-2, k=3 and k=-3 , each on a separate graph. Finally, plot the signal x(t) as a sum of these harmonics.

[Marc]

Sounds like homework. What have you done so far?

Answer 1

[Sean de Wolski]

Well in order to run the code and get snapshots along the way. Use the publish functionality. This can be found from the Editor's Publish tab or by running publish.

doc publish

For more info.

[Sean de Wolski]

It says snapshots in the question title...

[Image Analyst]

The hints and code I gave should be sufficient. Anymore and I'd basically just be doing the whole thing for you. And I bet you're supposed to at least put in some effort yourself. Or is it allowable for your homework to just ask someone else to develop the complete solution for you and you turn in their work? I really can't add anymore without taking away any possibility that you'd be able to contribute anything.

Answer 2

[Image Analyst]

So start writing. You'll probably find these functions helpful: subplot(), plot(), sin(), cos(). Like

xFor1Term = sin(...... whatever
subplot(4,1,1);
plot(xFor1Term , 'r*-', 'LineWidth', 3);
grid on;

xFor2Term = sin(...... whatever
subplot(4,1,2);
plot(xFor2Term , 'r*-', 'LineWidth', 3);
grid on;

and so on.

[Sean de Wolski]

doc subplot

[Image Analyst]

4 rows of plots, 1 column of plots. The third number is the plot number going from upper left to lower right. So if you had

subplot(5,4,10);

you would have 5 rows and 4 columns, or 20 possible plot locations. Then 10 means the 10th one, which is the third row, second one in from the left.

   1  2  3  4
   5  6  7  8
   9 10 11 12
  13 14 15 16
  17 18 19 20