How to work on fprintf in fopen?
이전 댓글 표시
Hi team,
I am using following code
[ftxt,msg] = fopen([textpath keyword '_summary.txt' ],'w');
fprintf(ftxt, 'Summary sheet of %12s\n\n', TR);
and i am getting error as
Error using fprintf
Invalid file identifier. Use fopen to generate a valid file identifier.
Please help me solving this problem.
답변 (1개)
Wayne King
2013년 12월 23일
0 개 추천
What is msg? That is the system-dependent error message returned by fopen. I'm assuming the value of txt is -1 meaning the fopen() operation did not work.
댓글 수: 2
Radhika
2013년 12월 23일
Wayne King
2013년 12월 23일
I'm afraid you need to provide us with more information than you have given. Are we supposed to know what textpath is or keyword?
카테고리
도움말 센터 및 File Exchange에서 Data Type Conversion에 대해 자세히 알아보기
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