How Can I Change the Function Interp2? I Wrote The Following Code But The Data Is Not Getting Fetched.What To Do For The Same?
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r=0:1:7;
theta=0:2:4;
scan_lines=[1 1 2 3 4 5 6 7;2 3 4 5 6 7 8 9;3 4 5 6 7 8 9 10];
M=length(r);
N=length(theta);
P=0:.5:7;
Q=0:1:4;
[r_cart,theta_cart]=meshgrid(P,Q);
% K{i,j} ={r_cart,theta_cart};
m=length(P);
n=length(Q);
% Vq=0;
for i=1:1:N-1
del_theta=theta(i+1)-theta(i);
for j=1:1:M-1
del_r=r(j+1)-r(j);
for x=1:1:n
for y=1:1:m
delta=1/(del_theta*del_r);
a=(theta_cart(x)-theta(i))*(r_cart(y)-r(j));
b=(theta_cart(x)-theta(i))*(r(j+1)-r_cart(y));
c=(theta(i+1)-theta_cart(x))*(r_cart(y)-r(j));
d=(theta(i+1)-theta_cart(x))*(r(j+1)-r_cart(y));
end
end
end
end
% V=interp2(r,theta,scan_lines,r_cart,theta_cart);
for i=1:1:n
for j=1:1:m
Vq=delta*((a.*x(i+1,j+1))+(b.*x(i+1,j))+(c.*x(i,j+1))+(d.*x(i,j)));
end
end
댓글 수: 1
rahna
2013년 12월 17일
편집: Walter Roberson
2013년 12월 17일
답변 (2개)
Andrei Bobrov
2013년 12월 17일
편집: Andrei Bobrov
2013년 12월 17일
You can use griddedInterpolant:
sl = [1 1:7;2:9;3:10];
r = 0:7;
theta = 0:2:4;
[x,y] = ndgrid(theta,r);
F = griddedInterpolant(x,y,sl)
P = 0:.5:7;
Q = 0:.1:4;
[Qm,Pm] = ndgrid(Q,P);
V = F(Qm,Pm);
or used old function griddata:
sl = [1 1:7;2:9;3:10];
r = 0:7;
theta = 0:2:4;
[x,y] = ndgrid(theta,r);
P = 0:.5:7;
Q = 0:.1:4;
[Qm,Pm] = ndgrid(Q,P);
V = griddata(x,y,sl,Qm,Pm);
Walter Roberson
2013년 12월 17일
You are overwriting all of "a", "b", "c", and "d" in every iteration of your inner-most loop.
As your overwriting is inside a loop nested four down, "i", "j", "x", "y", in order to extract the data for use outside the loops, you would need to store to a(i,j,x,y), b(i,j,x,y) and so on.
You would then run into the difficulty that your Vq is overwritten in each iteration of the second set of nested loops. As you are accessing all of "a" and "b" and so on there, and we have determined that those would have to be four-dimensional matrices, then each Vq entry would have to be a four-dimensional matrix. As that is within two nested loops, you would therefore need to be constructing a six-dimensional matrix answer:
Vq(:,:,:,:,i,j) = ....
What you are going to do with a six-dimensional result is something I am sure I do not understand.
Perhaps the structure of your code is in error rather than the syntax.
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