I have this info_circuitos.Name_circuito. I need to shearch in a name. but the struct have accents. a e i o u OR A E I O U. Could have accent in any of that letter.
I want to create a new info_circuitos.Name_circuito without accent Help pls.
Thanks

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sixwwwwww
sixwwwwww 2013년 12월 9일
how many structs you have?
5mid
5mid 2013년 12월 9일
편집: 5mid 2013년 12월 9일
It can be of any size.
Mónaco
Alemanha Could be like that
Austrália
Monreal
Espanha
Itália

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sixwwwwww
sixwwwwww 2013년 12월 9일
편집: sixwwwwww 2013년 12월 9일

2 개 추천

you can do it like this:
names = {files.name};
str = {'Á', 'É', 'Í', 'Ó', 'Ú', 'á', 'é', 'í', 'ó', 'ú'};
strreplace = {'A', 'E', 'I', 'O', 'U', 'a', 'e', 'i', 'o', 'u'};
for j = 1:length(names)
for i = 1:numel(str)
names{j} = regexprep(names{j}, str{i}, strreplace{i});
end
end
Good luck!

댓글 수: 14

I will try. I have already
nome = input('\nIntroduza o nome do circuito a remover: ','s');
indice_nome = strfind(lower({info_circuitos.Nome_circuito}), lower(nome));
I will try.
Thanks
5mid
5mid 2013년 12월 9일
But if I search for mona it finds Mónaco?
you are welcome. if you want to avoid the loop then you can use the following method as well:
names = {files.name};
str = '[aeiou]';
startIndex = regexp(names,str);
It will find whether a vowel exist in names and return its starting index
5mid
5mid 2013년 12월 9일
It will change for example in Austrália the 'á' for a?
I don´t understand how this does that.
5mid
5mid 2013년 12월 9일
편집: 5mid 2013년 12월 9일
I think I don´t want that. I want like
chars_old = 'ÁÉÍÓÚáéíóú';
chars_new = 'AEIOUaeiou';
str = info.Nome_circuito;
[tf,loc] = ismember(str, chars_old);
str(tf) = chars_new( loc(tf) );
But to change the structure.
I just tried the following code:
names = 'Austrália';
str = '[aeiou]';
startIndex = regexp(names,str);
and it is giving me result:
[2, 8, 9] for u, i and a
It shows that MATLAB is not finding á as a.
5mid
5mid 2013년 12월 9일
편집: 5mid 2013년 12월 9일
But this don´t change my struct. I think i´m not understanding what you are trying to say to me. This is my struct info.names
Mónaco
Alemanha
Austrália
Monreal
Espanha
Itália
I want it like
Monaco
Alemanha
Australia
Monreal
Espanha
Italia
you can do it as follow:
names = {files.name};
str = {'Á', 'É', 'Í', 'Ó', 'Ú', 'á', 'é', 'í', 'ó', 'ú'};
strreplace = {'A', 'E', 'I', 'O', 'U', 'a', 'e', 'i', 'o', 'u'};
for j = 1:length(names)
for i = 1:numel(str)
names{j} = regexprep(names{j}, str{i}, strreplace{i});
end
end
I hope it solves your problem.
5mid
5mid 2013년 12월 9일
편집: 5mid 2013년 12월 9일
Man you´re god!!
Thanks, thats what I want.
I can´t choose you answer
sixwwwwww
sixwwwwww 2013년 12월 9일
편집: sixwwwwww 2013년 12월 9일
you are welcome and why you can't choose my answer?
5mid
5mid 2013년 12월 9일
forget... The corret option is not the first.
sixwwwwww
sixwwwwww 2013년 12월 9일
ok i replace it with the correct one
Walter Roberson
Walter Roberson 2013년 12월 9일
This code does not change the structure, just finds the equivalent strings.
5mid
5mid 2013년 12월 9일
Yes true, but with that I've done what I want.

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추가 답변 (1개)

Walter Roberson
Walter Roberson 2013년 12월 9일
편집: Walter Roberson 2013년 12월 9일

0 개 추천

Assuming ISO-8859-1 rather than full Unicode:
This code is untested.
function new_structure = remove_accents_from_struct(old_structure)
% Note: this code is only designed for size(structure) = 1 x 1
% and does not descend recursively into substructures.
old_fields = fieldnames(old_structure);
new_fields = cellfun( @remove_accents_from_string, old_fields, 'Uniform', 0);
if isequal(old_fields, new_fields) %optimization when there are no accents
new_structure = old_structure;
return
end
num_fields = length(old_fields);
% create empty structure populated with the translated field names but not their contents
new_structure = cell2struct( cell( num_fields, 1 ), new_fields );
% now copy the field contents over
for K = 1 : num_fields
new_structure.(new_fields{K}) = new_structure.(old_fields{K});
end
end
function newS = remove_accents_from_string(S)
% table extracted from % http://core.trac.wordpress.org/browser/tags/3.7.1/src/wp-includes/formatting.php
accented_chars = [ ...
char(128), char(131), char(138), char(142), char(154), ...
char(158), char(159), char(162), char(165), char(181), ...
char(192), char(193), char(194), char(195), char(196), ...
char(197), char(199), char(200), char(201), char(202), ...
char(203), char(204), char(205), char(206), char(207), ...
char(209), char(210), char(211), char(212), char(213), ...
char(214), char(216), char(217), char(218), char(219), ...
char(220), char(221), char(224), char(225), char(226), ...
char(227), char(228), char(229), char(231), char(232), ...
char(233), char(234), char(235), char(236), char(237), ...
char(238), char(239), char(241), char(242), char(243), ...
char(244), char(245), char(246), char(248), char(249), ...
char(250), char(251), char(252), char(253), char(255) ];
unaccented_chars = 'EfSZszYcYuAAAAAACEEEEIIIINOOOOOOUUUUYaaaaaaceeeeiiiinoooooouuuuyy';
newS = S;
[tf, idx] = ismember(S, accented_chars);
newS(tf) = unaccented_chars(idx);
end

댓글 수: 2

5mid
5mid 2013년 12월 9일
Wow to much complex, but should work
Walter Roberson
Walter Roberson 2013년 12월 9일
You said you could have an accent on any letter, so I could not assume that you only want to deal with grave accents on English vowels.
Most of the rest of the length is comments or efficiency.

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