How to select columns based on a known repeated pattern.

조회 수: 2(최근 30일)
Matt 2013년 12월 5일
답변: Andrei Bobrov 2013년 12월 5일
I have data that came from excel and I want to grab the data without all the comments. I have imported the data into matlab but now I am having trouble selecting it cleanly. If the data is in a variable called raw I do the following.
data = raw(:,28:22:end);
data = [data, raw(:,29:22:end)];
data = [data, raw(:,30:22:end)];
data = [data, raw(:,31:22:end)];
data = [data, rwa(:,32:22:end)];
The problem with this is I have to reorder everything afterwards to get the columns back in the right order. I want to select all the columns like:
data = raw(:,[28:32]:22:end);
or something similiar. I figure there must be some ultra fancy vector way of doing this in 1 shot.

채택된 답변

Andrei Bobrov
Andrei Bobrov 2013년 12월 5일
data = raw(:,bsxfun(@plus,29:32,22*(0:floor((size(raw,2)-32)/22))'));

추가 답변(2개)

the cyclist
the cyclist 2013년 12월 5일
One marginally better possibility:
data = raw(:, [28:22:end 29:22:end 30:22:end 31:22:end 32:22:end]);

Kelly Kearney
Kelly Kearney 2013년 12월 5일
Not quite one shot, but a little less typing:
n = size(raw, 2);
idx = bsxfun(@plus, (1:22:n)', 28:32);
idx = idx(idx <= n);
data = raw(:,idx);
  댓글 수: 1
Matt 2013년 12월 5일
2 minor things but this is good.
idx = bsxfun(@plus, (1:22:n)', 27:31);
idx = sort(idx(idx <= n)); % sorts the columns in the right order

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