line of code help!

I was wondering if someone could help me diagnose what the 3rd to last line of code - y{jj,ii}(:,(ii+1):end) = x{jj}(:,(ii+1):end); -- does for this block.

for jj = 1:N      
y{jj,1} = ones(N+1);     
y{jj,1}(:,2:end) = x{jj}(:,2:end);    
A(jj,1) = det(y{jj,1});   
y{jj,ii} = ones(N+1);                                             
y{jj,ii}(:,1:(ii-1)) = x{jj}(:,1:(ii-1));                          
y{jj,ii}(:,(ii+1):end) = x{jj}(:,(ii+1):end);                      
A(jj,ii) = det(y{jj,ii});                                         
    end

Answer 1

[dpb]

 for jj = 1:N      
   ...
   y{jj,ii}(:,1:(ii-1)) = x{jj}(:,1:(ii-1));                          
   y{jj,ii}(:,(ii+1):end) = x{jj}(:,(ii+1):end);                      
   ...
 end

Just loading the columns of the array from (ii+1)th to the last similarly as does the preceding line load from the first column to the (ii-1)th. The two lines together load all columns excepting for ii.

doc end

if it's that that's confusing -- it's a builtin that's position-sensitive as to what it returns, specifically.