How to find first nonzero element/first '1' per row and set other elements to zero without loops in 3D Matrix
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I've a Matrix f.ex. like
A=[0,1,1,0; 1,0,0,1;0,0,0,1;0,1,1,1]; A =
0 1 1 0
1 0 0 1
0 0 0 1
0 1 1 1
only in 3D. So for example a Matrix like this only 100times (size(A)=4 x 4 x 100). Of course different shape/form of the '1s' and '0s'.
I want to as a result only the first '1' of each row and all other elements or further "1" to zero. The result should be:
B=[0,1,0,0;1,0,0,0;0,0,0,1;0,1,0,0];
B =
0 1 0 0
1 0 0 0
0 0 0 1
0 1 0 0
again, a hundred times. So the Result would be again size(B)= 4 x 4x 100.
If it was a 2D-matrix I'd use this: [Y,I] = max(A, [], 2); B = zeros(size(A)); B(sub2ind(size(A), 1:length(I), I')) = Y;
But that doesn't work for a 3Dim-Matrix...And I don't want to use for loop. Thanks!
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추가 답변 (2개)
Jos (10584)
2013년 12월 3일
Something like this?
% input
A = round(rand(5,6,2))
% engine
isOne = A == 1 ;
B = isOne & cumsum(isOne,2) == 1
댓글 수: 4
Andrei Bobrov
2013년 12월 3일
+1
Tim
2013년 12월 3일
Simon
2013년 12월 3일
Great!
Chang Sun
2015년 12월 6일
so simple!
Simon
2013년 12월 3일
Hi!
Why don't you want loops? It is the easiest way. Try this:
ix = 1:size(A, 1);
% loop over al columns
for col = 1:size(A, 2)-1;
% find line with '1' in current column
ind = (A(ix, col) == 1);
% set rest of found lines to '0'
A(ix(ind), col+1:end) = 0;
% delete found lines from index -> no check needed anymore!
ix = ix(~ind);
% if we checked all lines we have finished -> break out of loop
if isempty(ix)
break
end
end
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