??? Index exceeds matrix dimensions. Error in ==> Untitled at 267 if length(W{i})==0;

{1x3 cell}    {1x2 cell}    {1x4 cell}
W{2}{1}={[1 2],[],[2 5 3]}
for i=1:size(W,2)
  if length(W{i})==0;
      W(cellfun('isempty',W))=[];%odstranenie prazdnych miest
  else
      %zmaze prazdne miesta v poli
      W{i}(cellfun(@isempty,W{i})) = [];
  end
end
W

 I want to delete empty place in cell,2 events may occur once Z ={1x3 cell} [] {1x2 cell} [] {1x4 cell} or can be Z{1}=   [1x3 double]    [1x3 double]    [1x3 double] [] []

Thanks.

Answer 1

[Azzi Abdelmalek]

Try this

idx=cellfun(@isempty,W{2}{1});
W{2}{1}(idx)=[]

[Tomas]

it does not work

i have code

   for i=1:size(W,2)
                  for j=length(W{i})
                    if j~=0
                 W{i}(cellfun(@isempty,W{i})) = [];

     else

             W(cellfun('isempty',W))=[];%odstranenie prazdnych miest

     end
                  end
              end

W

??? Index exceeds matrix dimensions.

Error in ==> Untitled at 259 for j=length(W{i})

i want if treated W(cellfun('isempty',W))=[]; that all completed. what do i use,so I ended the loop

[Azzi Abdelmalek]

If you post an example, it will be useful

[Tomas]

i have cell

The first iteration will Z={1x5cell} {1x4cell} in cell Z{1}=[] [1x3 double] [1x3 double] [1x3 double] ] [] Z{2}=[] [] [1x3 double] [1x3 double]

 I will use   for i=1:size(Z,2)
 Z{i}(cellfun(@isempty,Z{i})) = [];

The second iteration Z= [] {1x4cell} i will use Z(cellfun('isempty',Z))=[]

I want to write in one loop i.

I need to remove empty space automatically.

[Azzi Abdelmalek]

I will give an example

W{1}{1}={[] 1:3   3:5    1:3 [] }
W{2}{1}={[] [] 1:3  1:3 } 
idx=cellfun(@isempty,W{2}{1});W{2}{1}(idx)=[]
celldisp(W{2})

[Tomas]

i need when i have Z=[] {1x3 cell} {1x2 cell} i want to delete [] if length(Z(1))==0 error message

? Undefined function or method 'eq' for input arguments of type 'cell'.