Finding the norm of a matrix using for-loops and conditional statements

Alright, so I'm having a bit of trouble with an example for MATLAB. I'm trying to find the conditional number of any square matrix, which normally isn't too difficult. However, instead of using the norm function to find the norm of the matrix, I am to use loops and conditional statements. I'm not completely sure where to start.
I know how to find the norm on paper - I take the absolute value of each number of the matrix, then add up the columns. The largest number, then, is the norm of the matrix. How might I translate that over into MATLAB?
EDIT: This is how what I've gotten thus far. The sums make sense, but I don't know how to edit it so that it'll work for any square matrix.
A= [2 3 4; 4 7 6; -11 85 9;];
invA= inv(A);
mn=size(A);
n=length(A);
for i=1:1:n-2
for j=1:1:n-2
sum_1=abs(A(i,1)) + abs(A((i+1),1) + abs(A((i+2),1)))
sum_2=abs(A(i,2)) + abs(A((i+1),2)) + abs(A((i+2),2))
sum_3=abs(A(i,3)) + abs(A((i+1),3)) + abs(A((i+2),3))
end
end

댓글 수: 3

Why not just use cond()
I'm supposed to use loops and conditional statements - I can't use max/cond/sum/similar commands.
Matt J
Matt J 2013년 11월 24일
편집: Matt J 2013년 11월 24일
I know how to find the norm on paper - I take the absolute value of each number of the matrix, then add up the columns.
That is the L1 norm, not the more standard L2 norm.

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 채택된 답변

Matt J
Matt J 2013년 11월 24일
편집: Matt J 2013년 11월 24일
Hint:
B=abs(A);
accum=0;
for i=1:size(B,1)
accum=accum+B(i,:);
end

댓글 수: 2

That makes sense, I appreciate it. What does the : signify in the B(i,:); portion?
Nevermind, figured what the : was.

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추가 답변 (1개)

Chris
Chris 2013년 11월 25일

0 개 추천

I greatly appreciate that little hint you gave me - that little nudge in the right direction was just what I needed.

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2013년 11월 24일

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2013년 11월 25일

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